Question

Python 3.7.4:

The current calendar, called the Gregorian calendar, was introduced in 1582. Every year divisible by four was created to be a leap year, with the exception of the years ending in 00 (that is, those divisible by 100) and not divisible by 400. For ­instance, the years 1600 and 2000 are leap years, but 1700, 1800, and 1900 are not. Write a program that requests a year as input and states whether it is a leap year. We need to run this as many times as the user wants to check for leap years.

Below was marked incorrect for me. I need to put it in a while loop. Also, I'm curious if there is a way to do it without def? Do we have to call main? Sorry for all of the newbie questions. Thank you!

----------------------

def leap(year):
    if(year % 400 == 0):
        return True
    elif year % 100 == 0:
        return False
    elif year%4 == 0:
        return True
    else:
        return False
def main():
    year = int(input("Enter year: "))
    if(leap(year)):
        print(year,"is a leap year")
    else:
        print(year, "is not a leap year")
main()

Answer 1

Program code in python:

import sys #helps to use sys.exit to exit from the program

def leap(year): #function to check for leap year
if(year % 400 == 0):
return True
elif year % 100 == 0:
return False
elif year%4 == 0:
return True
else:
return False
def main(): #function to enter year
year = int(input("Enter year: "))
if(leap(year)):
print(year,"is a leap year")
else:
print(year, "is not a leap year")
replayMain()
  
def replayMain(): #function to get the choice to continue
ch = int(input("Do you want to continue: Press 1 to continue and 0 to exit.... "))
if(ch == 1):
main()
else:
sys.exit
main() #main function call

Screenshots attached below:

Screenshot of the python code:

Screenshot of sample output:

Please "Like" if this helped!  Good luck!

Editted as per request to use something instead of sys.exit.....

You can also use break instead of sys.exit.

The code will be as :

def leap(year): #function to check for leap year
if(year % 400 == 0):
return True
elif year % 100 == 0:
return False
elif year%4 == 0:
return True
else:
return False
def main(): #function to enter year
year = int(input("Enter year: "))
if(leap(year)):
print(year,"is a leap year")
else:
print(year, "is not a leap year")
replayMain()
  
def replayMain(): #function to get the choice to continue
ch = int(input("Do you want to continue: Press 1 to continue and 0 to exit.... "))
while ch == 0:
break #exits the program
else:
main()
main() #main function call

code screenshot:

output:

Good luck!