Question

In Java Please!!!

5.24 LAB: Leap year A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is: 1712 the output is: 1712 - leap year Ex: If the input is: 1913 the output is: 1913 - not a leap year

Answer 1

//LabProgram.java
import java.util.Scanner;
public class LabProgram {
    public static boolean isLeapYear(int userYear){
        if(userYear % 4 == 0 && userYear % 100 != 0){
            return true;
        }
        else if(userYear % 400 == 0){
            return true;
        }
        return false;
    }

    public static void main(String args[]){
        Scanner scnr = new Scanner(System.in);
        int inputYear;
        boolean isLeapYear;

        isLeapYear = false;
        inputYear = scnr.nextInt();

        isLeapYear = isLeapYear(inputYear);
        if(isLeapYear){
            System.out.println(inputYear+" - a leap year");
        }
        else{
            System.out.println(inputYear+" - not a leap year");
        }
    }
}