A Student in mass transfer operation lab accidently spills 10 litres of gasoline, which quickly spreads...

A Student in mass transfer operation lab accidently spills 10 litres of gasoline, which quickly spreads over a level surface of area 10 m2 . Estimate the time required for the gasoline to evaporate into the stagnant air above the surface of the liquid. The diffusivity of gasoline in air is 0.65 m2 h -1 . The air temperature is 298 K. Evaporation may be assumed to take place through a film of air of 2 mm thickness. Vapour pressure of gasoline at 298 K is 76 mmHg. The density of gasoline is 720 kg m-3 and the molecular weight of gasoline is 200. The operation takes place at 1 atm pressure

Expert Solution

SOLUTION.

We have to calculate time required to evaporate gasoline .

This is Diffusion of gasoline in air given by the ficks law of Diffusion which Given as

Na = D/(RTZ) *P*ln(P-PA2/P-PA1)

Na is fluix and D is Diffusivity ,P is total pressure and PA1 and PA2 is pressure of gasoline in gasoline layer and in the air.

Z is thickness of stagnant air layer 2 mm.

D=0.65 m²/hr =0.65/3600=1.8055*10^-4 m²/sec.

ANSWER ,

Time required to evaporate all gasoline is 9.2545 sec .

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