Question

PYTHON

def find_treasure(mapfile):
with open (mapfile, 'r') as f:
data = f.readlines()
for i, row in enumerate(data):
for j, column in enumerate(row):
if 'S' in column:

print((i,j))
return (i,j)
#This is what mapfile contains   
#AAASAAA
#AASSSAA
#AAASAAA
#Need to find the coordinate of the middle S

Answer 1

def find_treasure(mapfile):
        with open (mapfile, 'r') as f:
                data = f.readlines()
        for i, row in enumerate(data):
                for j, column in enumerate(row):
                        
                        # Check the current cell should not be on any edges
                        # also, It should be surrounded by all side from 
                        # S
                        if i > 0 and j > 0 and i < len(data) - 1 and j < len(data[i]) - 1\
                                and column == 'S' and row[j-1] == 'S' and row[j+1] == 'S'\
                                and data[i-1][j] == 'S' and data[i+1][j] == 'S':
                                print(i, j)
                                return (i, j)
                        

#This is what mapfile contains   
#AAASAAA
#AASSSAA
#AAASAAA
#Need to find the coordinate of the middle S
find_treasure('map.data')  # Call like this.

**************************************************
You have given very less info in the question on what are the conditions.. I am assuming that, we need to find the 'S', which has all its neighbors(up/Down/left/right) as 'S'. I coded based on this fact.. If any issues,please ask.

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