In: Statistics and Probability
Suppose the National Transportation Safety Board wants to examine the safety of compact cars, midsize cars, and full-size cars. It collects a sample of three for each of the treatments (cars types). Test the claim that the mean pressure applied to the driver's head during a crash is equal for all three types of cars. Use α = 0.05
| Compact Cars | 643 | 655 | 702 | 
| Midsize Cars | 469 | 427 | 525 | 
| Full-size Cars | 484 | 456 | 402 | 
Show your 6 steps labeled in order in the box below.
| count, ni = | 3 | 3 | 3 | |||
| mean , x̅ i = | 666.667 | 473.67 | 447.33 | |||
| std. dev., si = | 31.182 | 49.166 | 41.681 | |||
| sample variances, si^2 = | 972.333 | 2417.333 | 1737.333 | |||
| total sum | 2000 | 1421 | 1342 | 4763 | (grand sum) | |
| grand mean , x̅̅ = | Σni*x̅i/Σni = | 529.22 | 
| square of deviation of sample mean from grand mean,( x̅ - x̅̅)² | 18890.975 | 3086.420 | 6705.790 | ||
| TOTAL | |||||
| SS(between)= SSB = Σn( x̅ - x̅̅)² = | 56672.926 | 9259.259 | 20117.370 | 86049.55556 | |
| SS(within ) = SSW = Σ(n-1)s² = | 1944.667 | 4834.667 | 3474.667 | 10254.0000 | 
no. of treatment , k =   3
df between = k-1 =    2
N = Σn =   9
df within = N-k =   6
  
mean square between groups , MSB = SSB/k-1 =   
43024.7778
  
mean square within groups , MSW = SSW/N-k =   
1709.0000
  
F-stat = MSB/MSW =    25.1754
P value =   0.0012
| SS | df | MS | F | p-value | F-critical | ||
| Between: | 86049.56 | 2 | 43024.78 | 25.18 | 0.0012 | 5.14 | |
| Within: | 10254.00 | 6 | 1709.00 | ||||
| Total: | 96303.56 | 8 | |||||
| α = | 0.05 | ||||||
| conclusion : | p-value<α , reject null hypothesis | 
Not all means are equal.
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