Question

Match each function type correctly.

Question 1 options:

In this parameter type, the memory location of the variables from the invoking function are passed to the called function. In this parameter type, a copy of the variables from the invoking function are passed to the called function.

1. Pass By Value 2. Pass By Reference

Answer 1

Answers:

2. Pass By Reference
In this parameter type, the memory location of the variables from the invoking function are passed
to the called function.
-> In this type of argument passing, what ever changes done to the argument in the called function,
will be reflected in the calling function also as the same variable's memory location is passed.
-> This is useful when the user wants to pass an array to a function or.
-> This can also be used to return multiple values from the called function to the calling function.

Ex :
void pass_by_reference(int *a) {
   *a = 10;
}

int main() {
   int x = 5;
   printf("value of x : %d\n"); // 5 will be printed
   pass_by_reference(&x); //& is used to pass a variable by reference
   printf("value of x : %d\n"); // 10 will be printed
}

1. Pass By Value
In this parameter type, a copy of the variables from the invoking function are passed
to the called function.
-> In this type of arument passing, a copy of a original variable is passed to the calling function,
hence the changes done to the variable inside the called function are only visible inside the called
function and the original variable value will not be changed.
-> This is used when we do not want the called function to change the original value of the variable.

Ex :
void pass_by_value(int *a) {
   *a = 10;
}

int main() {
   int x = 5;
   printf("value of x : %d\n"); // 5 will be printed
   pass_by_value(x);
   printf("value of x : %d\n"); // 5 will be printed
}