In: Statistics and Probability
A cognitive retraining clinic assists outpatient victims of head injury, anoxia, or other conditions that result in cognitive impairment. Each incoming patient is evaluated to establish an appropriate treatment program and estimated length of stay. To see if the evaluation teams are consistent, 12 randomly chosen patients are separately evaluated by two expert teams (A and B) as shown.
Estimated Length of Stay in Weeks | ||||||||||||
Patient | ||||||||||||
Team | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 |
A | 38 | 26 | 25 | 46 | 47 | 23 | 41 | 23 | 18 | 28 | 31 | 52 |
B | 37 | 32 | 35 | 16 | 51 | 37 | 40 | 33 | 16 | 33 | 42 | 34 |
(b) Specify the decision rule at the .10 level of significance.(Round your answers to 3 decimal places. A negative values should be indicated by a minus sign.)
Reject the null hypothesis if the p-value is (Click to select)less thangreater than 0.10 or if tcalc < or tcalc > .
(c) Find the test statistic tcalc. (Round your answer to 3 decimal places. A negative value should be indicated by a minus sign.)
tcalc
(d) Find the p-value. (Round your answer to 3 decimal places. A negative value should be indicated by a minus sign.)
p-value
See the data collected on same person so this data pairs are dependent
For dependent data set we use pair t test.
Here we want to test "whether the evaluation teams are consistent or not".
Let's write null hypothesis (H0) and altermative hypothesis(H1)
Let's used excel :
Step 1) Enter the given data in excel columns.
Step 2) Click on Data >>>Data Analysis >>> t-Test: Pair Two sample for Means
then click on OK
In variable 1 Range select data of team A
In variable 1 Range select data of team B
Hypothesized mean difference : 0
Select Labels
Then click on Output range and select any empty cell
See the following box
Then click on OK
So we get the following output
From the above output we get,
p-value for two tailed = 0.861
t test statistic = -0.180
Critical values = -1.796 and t = 1.796
Decision rule based on p-value:
Decision rule:
1) If p-value < level of significance (alpha) then we reject null hypothesis
2) If p-value > level of significance (alpha) then we fail to reject null hypothesis.
Here p value = 0.8607 > 0.10 so we used 2nd rule.
That is we fail to reject null hypothesis
Conclusion : At 10% of level of significance there was not sufficient evidence that the two teams are consistent.
So we can say that the two teams are consistent.