Question

*C PROGRAMMING LANGUAGE*

a) Given an array of size n, sort the array using pointers using malloc or calloc. Examples: Input: n = 5, A= {33,21,2,55,4} Output: {2,4,21,33,55}

b) Write a function that declares an array of 256 doubles and initializes each element in the array to have a value equal to half of the index of that element. That is, the value at index 0 should be 0.0, the value at index 1 should be 0.5, the value at index 2 should be 1.0, and so on. your function must be called in the main. Also, declaring array and the size must be using heap.

Answer 1

SOLUTION A sorting using pointers:

#include<stdio.h>
#include<stdlib.h>
int main(){
   int n,i,temp,j;
   printf("Enter the number of elements in array\n");
   scanf("%d",&n);
   int *a;
   a=(int*)malloc(sizeof(int)*n);
   if(a==NULL){
       printf("Memory is not allocated\n");
       return 0;
   }
   printf("Enter the elements in array\n");
   for(i=0;i<n;i++){
       scanf("%d",a+i);//a+i is address
   }
   //sorting logic
   for(i=0;i<n;i++){
       for(j=0;j<n;j++){
           if(*(a+i)<*(a+j)){
               //swap a[i] and a[j]
               temp=*(a+i);
               *(a+i)=*(a+j);
               *(a+j)=temp;
           }
       }
   }
   printf("The sorted array is :\n");
   for(i=0;i<n;i++){
       printf("%d ",*(a+i));
   }
   return 0;
}

SCREENSHOT OF THE CODE:

OUTPUT OF THE CODE:

SOLUTION B:

#include<stdio.h>
#include<stdlib.h>
void function(double *a,int n){
   double j=0,k=2;
   int i;
   for(i=0;i<n;i++){
       //double/double is always double only
       a[i]=j/k; //values in the array are half
   j++;
   }
   for(i=0;i<n;i++){
       printf("%lf ",a[i]);
   }
}
int main(){
double *a;
//declares array of 256 numbers
a=(double*)malloc(sizeof(double)*256);

function(a,256);//calling function

}

SCREENSHOT OF THE CODE:

SCREENSHOT OF THE OUTPUT:

NOTE:

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