Question

Solve this question in C++ language. DO NOT use loops. Use recursive function. Keep the program simple.

Q (5) Suppose you have been given the task to design a text editor which will take any multiline text from user and then display the statistics like total number of characters i.e., characters_count (excluding the white space and punctuations), words_count, and redundant_words_count. Create a structure named Text_Editor having four type members namely inserted_text (of type string), characters_count (of type unsigned int), words_count (of type unsigned int), and redundant_words_count (of type unsigned int). The structure should also have member functions namely Insert_Text( ) for obtaining the multiline text from user and assigning to input_text member-variable. End of text insertion should be specified by ‘#’ character. Moreover, there should be a separate member-function of the created structure named Count_Ch( ), Count_Words( ), and Count_Redundant_Words( ) that should process the input text in order to calculate and print the relevant statistics. All these different tasks are to be implemented using recursion technique.                                (30 Points)

Answer 1

#include <iostream>
#include <string>
#include <bits/stdc++.h>
using namespace std;
struct Text_Editor{
    string inserted_text;
    int characters_count;
    int words_count;
    int redundant_words_count;
    void Insert_Text(string s){
        inserted_text=s;
    }
    int i=0;
    void Count_Ch(){//used to count characters
        char char_array[inserted_text.length()+1];//Declaring a char array
        strcpy(char_array, inserted_text.c_str());//storing text in a char array
        char ch=char_array[i++];//Iterating through every single character
        int c=(int)ch;//Storing the ASCII value of character "ch" in variable "c".
        //How to get an ASCII value of a char
        //for eg: if we want an ASCII value of 'a' then type convert that char to int
        //ASCII value of a=(int)'a'
        /*In the below if statement we are getting the ASCII value of 'a','z','A','Z'
        and checking the ASCII value of a char from char_array so that its ASCII value
         lies in the range of ASCII value of ('a','z') or ('A','Z') . in that way we are
        counting the number of characters in a string which are pure alphabets
        (ignoring spaces and other punctuation marks*/
        if((c>=(int)'a'&&c<=(int)'z')||(c>=(int)'A'&&c<=(int)'Z')){
            characters_count+=1;
        }
        if(i<=strlen(char_array)){
                Count_Ch();
            }
    }
    void Count_Words( ){
        /*Here we are getting the total number of characters in a string
        irrespective of spaces and punctuation marks*/
        words_count=inserted_text.length();
    }
    void Count_Redundant_Words( ){
        /*This is simple we know the number of characters without spaces
        punctuation marks and also we know the total number of characters in a string
        irrespective of spaces and punctuation marks
        so to find the number of redundant words
        redundant words=total characters(including spaces and punctuation)-characters(excluding spaces and punctuation)*/
        redundant_words_count=words_count-characters_count;
    }
};
int main()
{
    Text_Editor t;
    cout<<"Enter your text:";
    string s;
    getline(cin,s);
    t.Insert_Text(s);
    cout<<"Text entered is:"<<t.inserted_text;
    t.Count_Ch();
    cout<<"\nCharacters count:"<<t.characters_count;
    t.Count_Words();
    cout<<"\nWords count:"<<t.words_count;
    t.Count_Redundant_Words();
    cout<<"\nRedundant words count:"<<t.redundant_words_count;
    return 0;
    
}

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