Question

In: Math

In a random sample of 24 fifth graders who took an IQ test, the average score...

In a random sample of 24 fifth graders who took an IQ test, the average score was 101.48 with a standard deviation of 13.34. Assuming that the IQ scores are normally distributed, what will be the 98% confidence interval for the average IQ scores for all fifth graders?

Select the best answer.

96.3054 to 106.6546

95.5521 to 107.4079

96.8131 to 106.1469

94.6728 to 108.2872

Solutions

Expert Solution

Solution :

Given that,

= 101.48

s =13.34

n = 24

Degrees of freedom = df = n - 1 = 24- 1 = 23

At 98% confidence level the t is ,

= 1 - 98% = 1 - 0.98 = 0.02

  / 2 = 0.02 / 2 = 0.01

t /2,df = t0.01,23 = 2.4999

Margin of error = E = t/2,df * (s /n)

= 2.4999 * ( 13.34/ 24)

=6.8072

The 98% confidence interval for the average IQ scores for all fifth graders

- E < < + E

101.48 - 6.8072 < < + 101.48+6.8072

94.6728 < < 108.2872

94.6728 to 108.2872

CORRECT OPTION IS LAST

94.6728 to 108.2872


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