In: Statistics and Probability
Pretend you are a researcher interested in evaluating the IQ of a class of “gifted” fifth-graders to see whether their mean IQ is significantly higher than the mean IQ of the general population. You administer a standardized IQ test to the “gifted” fifth-grade class and the data are provided in “Raw Data.txt”. Assume it is known that the IQ test you are using has a mean of 100 and a standard deviation of 15 when given to fifth-graders in general. It is also known that the test scores of fifth-graders, in general, are normally distributed.
This is the Raw Data Set:
| Students | IQ Score |
| 1 | 109 |
| 2 | 116 |
| 3 | 115 |
| 4 | 103 |
| 5 | 115 |
| 6 | 106 |
| 7 | 102 |
| 8 | 112 |
| 9 | 118 |
| 10 | 119 |
| 11 | 117 |
| 12 | 120 |
| 13 | 113 |
| 14 | 118 |
| 15 | 120 |
| 16 | 121 |
| 17 | 119 |
| 18 | 116 |
| 19 | 118 |
| 20 | 110 |
| 21 | 100 |
| 22 | 103 |
| 23 | 107 |
| 24 | 112 |
| 25 | 111 |
| 26 | 108 |
| 27 | 100 |
| 28 | 100 |
| 29 | 102 |
| 30 | 118 |
I need to find:
Population Mean: 100 (which is already given in the hypothetical scenario)
Population Variance: (I need to find this one using the SD of 15, which was given in the hypothetical scenario)
Sample Mean:
Sample Size:
Let
be the mean IQ of a class of “gifted” fifth-graders
To test whethermean IQ of “gifted” fifth-graders is significantly higher than the mean IQ of the general population which is given as 100 with SD 15
It is to test
Population mean =100, population SD
=15 . Also given test scores are normally distributed
For testing a sample “gifted” fifth-graders of size, n = 30 is taken and their IQs are listed as follows in second column.
| 1 | 109 | |
| 2 | 116 | |
| 3 | 115 | |
| 4 | 103 | |
| 5 | 115 | |
| 6 | 106 | |
| 7 | 102 | |
| 8 | 112 | |
| 9 | 118 | |
| 10 | 119 | |
| 11 | 117 | |
| 12 | 120 | |
| 13 | 113 | |
| 14 | 118 | |
| 15 | 120 | |
| 16 | 121 | |
| 17 | 119 | |
| 18 | 116 | |
| 19 | 118 | |
| 20 | 110 | |
| 21 | 100 | |
| 22 | 103 | |
| 23 | 107 | |
| 24 | 112 | |
| 25 | 111 | |
| 26 | 108 | |
| 27 | 100 | |
| 28 | 100 | |
| 29 | 102 | |
| 30 | 118 |
The sample mean
is (sum of these 30 IQs)/30 =
Test statistics whcih following std normal distribution,

here
is the value of
under null hypothesis, which is 100.
From std normal table, at 5% level of significance,
= 1.645
The calculated value of test statistic z is greater than the table value 1.645. Hence it is to reject null hypothesis and conclude that the mean IQ of “gifted” fifth-graders is significantly higher than the mean IQ of the general population.