For
the differential equation (2 -x^4)y" + (2*x -4)y' + (2*x^2)y=0.
Compute the recursion formula for the coefficients of the power
series solution centered at x(0)=0 and use it to compute the first
three nonzero terms of the solution with y(0)= 12 , y'(0) =0
using matlab, compute and plot y [n] = x [n]* h [n],
where
a. x [n] = h [n] = a^n (0 <=n <=40) & a = 0.5
b. x [n] = cos [n]; h [n] = u [n]; n = 0:4:360
c. x [n] = sin [n] ; h [n] = a^n; n:4:360; a = 0.9
utility function u(x,y;t )= (x-t)ay1-a
x>=t, t>0, 0<a<1
u(x,y;t )=0 when x<t
does income consumption curve is
y=[(1-a)(x-t)px]/apy ?(my result, i used
lagrange, not sure about it)
how to draw the income consumption curve?
Use simulation to prove that when X ∼ N(0, 1), Z ∼ N(0, 1), Y =
X3 + 10X +Z, we have V ar(X +Y ) = V ar(X) +V ar(Y ) + 2Cov(X, Y )
and V ar(X −Y ) = V ar(X) + V ar(Y ) − 2Cov(X, Y ).
Given Fxy(x,y)=u(x)u(y)[1-Exp(-x/2)-Exp(-y/2)+Exp(-(x+y)/2)].
Note: The step functions mean that Fxy(x,y)=0 for either or both
x<0 and y<0. Any x or y argument range below zero must be
truncated at zero. Determine:
a) P{X<=1,Y<=2} Ans: 0.2487
b) P{0.5<X<1.5} Ans: 0.3064
c) P{-1.5<X<=2, 1<Y<=3} Ans: 0.2423