Question

In: Statistics and Probability

Question B: The following data report length of stay (LOS) for 10 patients of Dr. Jones...

Question B: The following data report length of stay (LOS) for 10 patients of Dr. Jones and 10 patients of Dr. Smith. What is the expected outcome (average outcome) for Dr. Smith? What is the expected outcomes if Dr. Jones if he was seeing Dr. Smith's patients? To answer this question, replace each outcome of Dr. Jones with average outcome of same type of patient seen by Dr. Smith. Is Dr. Smith more efficient than Dr. Jones?

Dr. Smith Patients Previous MI CHF Shock LOS
1 1 1 0 4
2 1 1 0 5
3 1 0 0 4
4 1 0 1 5
5 1 0 1 4
6 1 0 1 4
7 1 0 1 5
8 0 0 0 2
9 0 0 0 2
10 0 0 0 1
Dr. Jones Patients previous MI CHF Shock LOS
1 1 1 0 5
2 1 1 0 5
3 1 1 0 5
4 1 1 1 5
5 1 0 1 5
6 1 0 1 5
7 1 0 1 5
8 1 0 0 4
9 0 0 0 2
10 0 0 0 2

Solutions

Expert Solution

Explanation:-

Given sample size 'n' =10

Mean Or average of Dr smith patients

Mean Or average of Doctor Jones

Drsmithpatients

x

Doctor jones

y

  

4

5

0.4 0.5 0.16 0.25
5 5 1.4 0.5 1.96 0.25
4 5 0.4 0.5 0.16 0.25
5 5 1.4 0.5 1.96 0.25
4 5 0.4 0.5 0.16 0.25
4 5 0.4 0.5 0.16 0.25
5 5 1.4 0.5 1.96 0.25
2 4 -1.6 -0.5 2.56 0.25
2 2 -1.6 -2.5 2.56 6.25
1 2 -2.6 -2.5 6.76 6.25

Null Hypothesis:H0: There is no significant difference between Dr smith patients and Dr jones patients

Alternative Hypothesis: H1:Dr smith is more efficient than Dr jones

we will use the t - Test statistic

where

Level of significance  

Degrees of freedom

The Calculated value   at 5% level of significance

Null hypothesis is accepted

Conclusion:-

Dr smith patients is not more than efficient of Dr jones


Related Solutions

Stay Length of Stay (LOS) Total Costs 1 3 $2,613.91 2 10 $8,769.03 3 2 $2,448.60...
Stay Length of Stay (LOS) Total Costs 1 3 $2,613.91 2 10 $8,769.03 3 2 $2,448.60 4 3 $2,568.70 5 3 $1,936.19 6 5 $7,230.71 7 5 $5,342.61 8 3 $4,108.13 9 1 $1,596.91 10 2 $4,061.28 11 2 $1,761.53 12 5 $4,779.19 13 1 $2,078.30 14 3 $4,713.61 15 4 $3,946.68 16 2 $2,902.74 17 1 $1,438.85 18 1 $820.21 19 1 $3,309.41 20 6 $5,476.33 INTERCEPT Now that you have determined the answer, it is time to provide...
A statistic center compiles data on the length of stay by patients in​ short-term hospitals. A...
A statistic center compiles data on the length of stay by patients in​ short-term hospitals. A random sample of 2121 patients yielded the data on length of​ stay, in​ days, shown below. Complete parts​ (a) through​ (e) below. 24 4 5 18 4 14 55 23 23 7 10 5 9 1 20 25 5 18 19 14 2324 4 5 18 4 14 55 23 23 7 10 5 9 1 20 25 5 18 19 14 23. a....
Question: To what extent does gender influence length of hospital stay for MI patients ? Information...
Question: To what extent does gender influence length of hospital stay for MI patients ? Information on data set Which variables are you investigating? ID Length of hospital stay Gender What is the type of each variable? Numeric/Qualitative Quantitative Normal List the descriptive stats you will run on the data. Distribution Central Tendencies: Mean, Std, Dev, Mode, Median, Min, Max etc. What does each calculation tell you about the data? 65 Males, 35 Females The average LOS for males =...
In a population survey of patients in a rehabilitation hospital, the mean length of stay in...
In a population survey of patients in a rehabilitation hospital, the mean length of stay in the hospital was 12.0 weeks with a standard deviation equal to 1.0 week. The distribution was normally distributed. What is the percentile rank for each of the following z scores? Enter the percentile rank to the right of each z score. Assume a normal distribution. a) 1.23 _____ b) 0.89 ______ c) -0.46 _____ d) -1.00 ______
Researchers studied the length of hospital stay for the elderly patients in a psychiatric ward in...
Researchers studied the length of hospital stay for the elderly patients in a psychiatric ward in one of Phoenix hospitals. Their conclusion was that the mean length of hospital stay for all these patients was 26 days. The distribution was normal. Concerned citizens watch group want to verify the length of hospital stay by estimating it using a random sample of 40 patients. The mean length of hospital stay for this sample of patients is 23. Assume the length of...
The length of stay (in days) from 100 randomly selected hospital patients are presented in the...
The length of stay (in days) from 100 randomly selected hospital patients are presented in the table below. Suppose we want to test the hypothesis that the population mean length of stay at the hospital is less than 5 days. Conduct hypothesis using =.05.        2 3 8 6 4 4 6 4 2 5 8 10 4 4 4 2 1 3 2 10 1 3 2 3 4 3 5 2 4 1 2 9 1 7 17...
Three physicians were selected for a study to evaluate the length of stay for patients undergoing...
Three physicians were selected for a study to evaluate the length of stay for patients undergoing a major surgical procedure. All these procedures occurred in the same hospital and were without complications. Eight records were randomly selected from patients treated over the past 12 months. Physician Time A 9 A 12 A 10 A 7 A 11 A 13 A 8 A 13 B 10 B 6 B 7 B 10 B 11 B 9 B 9 B 11 C...
24. A hospital would like to determine the mean length of stay for its stroke patients....
24. A hospital would like to determine the mean length of stay for its stroke patients. They observe a random sample of 6 patients, the resulting length of stay of stroke patients are: 6, 7, 5, 8, 11, 2 (in days) Suppose the true length of stay follows normal distribution, a 95% confidence interval for population mean is ____. (4 decimal places) Use the information to answer Q25-27 A 98% confidence interval for the mean number of credit hours that...
The following data depict the length of delay in discharging 18 older patients to a long-term...
The following data depict the length of delay in discharging 18 older patients to a long-term care facility: 5,3,4,1,2,6,7,4,8,10,3,5,3,5, 4,6,7,9 Use Excel to find the mean, the mode, the median, the standard deviation, the range, the coefficient of skewness, the 3rd quartile, the 6th decile, and the 25th percentile.
Q 15 Question 15 Consider the following sample of 11 length-of-stay values (measured in days): 1,...
Q 15 Question 15 Consider the following sample of 11 length-of-stay values (measured in days): 1, 1, 3, 3, 3, 4, 4, 4, 4, 5, 7 Now suppose that due to new technology you are able to reduce the length of stay at your hospital to a fraction 0.5 of the original values. Thus, your new sample is given by .5, .5, 1.5, 1.5, 1.5, 2, 2, 2, 2, 2.5, 3.5 Given that the standard error in the original sample...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT