Question

In: Math

Q 15 Question 15 Consider the following sample of 11 length-of-stay values (measured in days): 1,...

Q 15 Question 15 Consider the following sample of 11 length-of-stay values (measured in days): 1, 1, 3, 3, 3, 4, 4, 4, 4, 5, 7 Now suppose that due to new technology you are able to reduce the length of stay at your hospital to a fraction 0.5 of the original values. Thus, your new sample is given by .5, .5, 1.5, 1.5, 1.5, 2, 2, 2, 2, 2.5, 3.5 Given that the standard error in the original sample was 0.5, in the new sample the standard error of the mean is _._. (Truncate after the first decimal.)

Solutions

Expert Solution

The standard error in the new sample = 0.5 * 0.5 = 0.25 = 2

                            

                                         

                    

                                 

                             

                            

milcah answered 2 months ago
Next > < Previous

Related Solutions

The average length of stay in U.S. hospitals 4.5 days. The length of stay in days...
The average length of stay in U.S. hospitals 4.5 days. The length of stay in days of a random sample of patients at a local hospital was recorded.    a. Use this data to construct a 99% confidence interval. What are the upper and lower bounds?    b. Based on your confidence interval, is the length of stay at this local hospital significantly different from the national average at the 1% significance level? Length of Stay (days) 3 6 3...
The average length of stay in U.S. hospitals 4.5 days. The length of stay in days...
The average length of stay in U.S. hospitals 4.5 days. The length of stay in days of a random sample of patients at a local hospital was recorded. 3,6,3,7,8,9,4,6,5,5,7,3,3,5,8,5 A). Use this data to construct a 99% confidence interval. What are the upper and lower bounds? B). Based on your confidence interval, is the length of stay at this local hospital significantly different from the national average at the 1% significance level?
The average length of a maternity stay in a U.S. hospital is 2.2 days with a...
The average length of a maternity stay in a U.S. hospital is 2.2 days with a standard deviation of 0.6 days. A sample of 25 women who recently gave birth is taken. Find the probability that the sample mean is greater than 2.4 days. Round your answer to the nearest hundredth.
The length of stay (in days) from 100 randomly selected hospital patients are presented in the...
The length of stay (in days) from 100 randomly selected hospital patients are presented in the table below. Suppose we want to test the hypothesis that the population mean length of stay at the hospital is less than 5 days. Conduct hypothesis using =.05.        2 3 8 6 4 4 6 4 2 5 8 10 4 4 4 2 1 3 2 10 1 3 2 3 4 3 5 2 4 1 2 9 1 7 17...
The length of maternity stay in U.S. hospitals is normally distributed, with mean of   3.5   days...
The length of maternity stay in U.S. hospitals is normally distributed, with mean of   3.5   days and a standard deviation of   1.2   days. We randomly survey   91   women who recently bore children in U.S. hospitals. Let   X=   maternity stay in U.S. hospital, and   X¯=   average maternity stay for a sample of size   91 .   X∼    (pick one) BPEN (  ,  ) .   X¯∼    (pick one) EPNB (  ,  ) .    What is the probability that the average stay is more than   3   days? P(X¯>3)=      ...
(15) Consider a sample of nine wait times measured in seconds at a drive through coffee...
(15) Consider a sample of nine wait times measured in seconds at a drive through coffee shop. The sample mean is 95 and the sample standard deviation is 23.516. The population mean and standard deviation are 100 and 20 respectively. (1) What is the size of the sampling error in this case? (3) What is the probability that the average wait time would be less than 80 seconds? (3) What is the probability that the average wait time would be...
1.Given a sample of the following values, what is the variance and standard deviation? {15, 5,...
1.Given a sample of the following values, what is the variance and standard deviation? {15, 5, 14, 11, 5} 2. Given the Contingency table below, calculate the probability that an individual drawn randomly would be Under 40 and wants a Smart Phone as a prize. Table of Prize Choice by Age Chosen Device Smart Phone Smart Watch Totals Ages Under 40 30 80 110 40 and Up 50 40 90 Totals 80 120 200
QUESTION 26 Consider RSA with p = 7 and q = 11. What are n and...
QUESTION 26 Consider RSA with p = 7 and q = 11. What are n and z? n z 4 points    QUESTION 27 Put the following wireless encryption protocols in order from most secure to least secure.       -       1.       2.       3.          WPA       -       1.       2.       3.          WEP       -       1.       2.   ...
Question B: The following data report length of stay (LOS) for 10 patients of Dr. Jones...
Question B: The following data report length of stay (LOS) for 10 patients of Dr. Jones and 10 patients of Dr. Smith. What is the expected outcome (average outcome) for Dr. Smith? What is the expected outcomes if Dr. Jones if he was seeing Dr. Smith's patients? To answer this question, replace each outcome of Dr. Jones with average outcome of same type of patient seen by Dr. Smith. Is Dr. Smith more efficient than Dr. Jones? Dr. Smith Patients...
Question 11 mystring.length() or mystring.size() will return the length of the string in mystring. Question 11...
Question 11 mystring.length() or mystring.size() will return the length of the string in mystring. Question 11 options: True False Question 12 To access an element of an array of structures you use the ________ operator. Question 12 options: Dot Bitwise Logical Comparison Question 13 Question 13 options: What would be printed from the following C++ program? #include #include using namespace std; struct Point { int x; int y; }; void makeTriangle(Point p[]); int main() { Point p[3]; int i; makeTriangle(p);...
ADVERTISEMENT
Subjects
ADVERTISEMENT
Latest Questions
ADVERTISEMENT