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Q 15 Question 15 Consider the following sample of 11 length-of-stay values (measured in days): 1,...

Q 15 Question 15 Consider the following sample of 11 length-of-stay values (measured in days): 1, 1, 3, 3, 3, 4, 4, 4, 4, 5, 7 Now suppose that due to new technology you are able to reduce the length of stay at your hospital to a fraction 0.5 of the original values. Thus, your new sample is given by .5, .5, 1.5, 1.5, 1.5, 2, 2, 2, 2, 2.5, 3.5 Given that the standard error in the original sample was 0.5, in the new sample the standard error of the mean is _._. (Truncate after the first decimal.)

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Expert Solution

The standard error in the new sample = 0.5 * 0.5 = 0.25 = 2

                            

                                         

                    

                                 

                             

                            

milcah answered 1 month ago
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