Question

Suppose a function receives a pointer as an argument. Explain how this function is declared within its calling function. In particular, explain how the data type of the pointer argument is represented. C++

Answer 1

Dear Student..

below i have written a complete C++ program which has a function which accept a pointer argument, the data type is an integer.

Read the comments carefully.

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Program:

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#include <iostream>

using namespace std;

//THis function recives sal as an pointer argument

void Salary_Inc(int *sal, int inc)
{
    //add the inc in the salary

    *sal = *sal+inc;
}

//start of the main function

int main()
{
    int salary=0, inc=0;

    cout<<"Enter the employee salary: ";

    cin>>salary;

    cout<<"Enter increase amount:";

    cin>>inc;

    //call the function which accept the address of salary as an argument and the increase amount

    Salary_Inc(&salary, inc);
  
    //display the final salary

    cout<<"Final salary: "<<salary<<endl;

    return 0;
}

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Sample Output:

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Kindly Check and Verify Thanks..!!!