Question

In: Physics

A 2.3 kg solid sphere (radius = 0.10 m ) is released from rest at the...

A 2.3 kg solid sphere (radius = 0.10 m ) is released from rest at the top of a ramp and allowed to roll without slipping. The ramp is 0.70 m high and 5.7 m long.

A.) When the sphere reaches the bottom of the ramp, what is its total kinetic energy?

B.) When the sphere reaches the bottom of the ramp, what is its rotational kinetic energy?

C.) When the sphere reaches the bottom of the ramp, what is its translational kinetic energy?

Solutions

Expert Solution

Given mass of sphere ,

radius of sphere ,

Vertical height of the ramp,

A.) When the sphere reaches the bottom of the ramp, what is its total kinetic energy?

Total kinetic energy will be equal to the initial potential energy

ANSWER:

=========================

Now find the velocity of sphere at the bottom of the ramp

Total kinetic energy is sum of rotational kinetic energy and translational kinetic energy

--------

Moment of inertia of solid sphere,

and angular velocity,

--------

=============

B.) When the sphere reaches the bottom of the ramp, what is its rotational kinetic energy?

ANSWER:

=========================

C.) When the sphere reaches the bottom of the ramp, what is its translational kinetic energy?

ANSWER:

=========================

genius_generous answered 8 months ago
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