Question

This is to be done using MIPS assembly language.

Display the following menus, ask user to select one item. If 1-3 is selected, display message “item x is selected”, (x is the number of a menu item), display menus again; if 0 is selected, quit from the program.

1. Menu item 1

2. Menu item 2

3. Menu item 3

0. Quit Please select from above menu (1-3) to execute one function. Select 0 to quit

Answer 1

Code:

.data
        menu:   .asciiz "1. Menu item 1\n2. Menu item 2\n3. Menu item 3\n0. Quit \nPlease select from above menu (1-3) to execute one function. Select 0 to quit\n"
        mess:   .asciiz "item "
        mess2:  .asciiz " is selected\n"
.text 
loop:   li $v0,4
        la $a0,menu
        syscall         # print the menu message 
        
        li $v0,5
        syscall         # accept input
        move $t0,$v0    # move input to $t0
        
        beq $t0,0,done  # if 0 end loop and move to done
        # print "Menu x is selected"
        li $v0,4
        la $a0,mess
        syscall
        li $v0,1
        move $a0,$t0
        syscall
        li $v0,4
        la $a0,mess2
        syscall
        j loop  # go for next iteration of loop

done:   nop

Code screenshot:

Sample output:

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Code has been added with screenshot. Please refer to them

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