In: Chemistry
what is the concentration of H+ ions after adding 5.41 mL of of 0.816 M NaOH to 65.7 mL of 1.97 M HNO3?
NaOH + HNO3 -----> NaNO3(aq) + H2O
5.41x0.816 65.7x1.97 0 0 initial concentrations
=4.414 =129.429
0 125.015 4.414 4.414 after reaction
Thus [H+] = 125.015/71.11= 1.758 M
The H+ ion concentration in the solution is 1.758M