Question

In: Computer Science

Convert 2.115 single-precision floating point binary format. Please show every single detail for upvote. Please do...

Convert 2.115 single-precision floating point binary format.
Please show every single detail for upvote.
Please do not answer otherwise.

Solutions

Expert Solution

Converting 2.115 to binary
   Convert decimal part first, then the fractional part
   > First convert 2 to binary
   Divide 2 successively by 2 until the quotient is 0
      > 2/2 = 1, remainder is 0
      > 1/2 = 0, remainder is 1
   Read remainders from the bottom to top as 10
   So, 2 of decimal is 10 in binary
   > Now, Convert 0.11500000000000021 to binary
      > Multiply 0.11500000000000021 with 2.     Since 0.23000000000000043 is < 1. then add 0 to result
      > Multiply 0.23000000000000043 with 2.     Since 0.46000000000000085 is < 1. then add 0 to result
      > Multiply 0.46000000000000085 with 2.     Since 0.9200000000000017 is < 1. then add 0 to result
      > Multiply 0.9200000000000017 with 2.  Since 1.8400000000000034 is >= 1. then add 1 to result
      > Multiply 0.8400000000000034 with 2.  Since 1.6800000000000068 is >= 1. then add 1 to result
      > Multiply 0.6800000000000068 with 2.  Since 1.3600000000000136 is >= 1. then add 1 to result
      > Multiply 0.36000000000001364 with 2.     Since 0.7200000000000273 is < 1. then add 0 to result
      > Multiply 0.7200000000000273 with 2.  Since 1.4400000000000546 is >= 1. then add 1 to result
      > Multiply 0.44000000000005457 with 2.     Since 0.8800000000001091 is < 1. then add 0 to result
      > Multiply 0.8800000000001091 with 2.  Since 1.7600000000002183 is >= 1. then add 1 to result
      > Multiply 0.7600000000002183 with 2.  Since 1.5200000000004366 is >= 1. then add 1 to result
      > Multiply 0.5200000000004366 with 2.  Since 1.0400000000008731 is >= 1. then add 1 to result
      > Multiply 0.040000000000873115 with 2.    Since 0.08000000000174623 is < 1. then add 0 to result
      > Multiply 0.08000000000174623 with 2.     Since 0.16000000000349246 is < 1. then add 0 to result
      > Multiply 0.16000000000349246 with 2.     Since 0.3200000000069849 is < 1. then add 0 to result
      > Multiply 0.3200000000069849 with 2.  Since 0.6400000000139698 is < 1. then add 0 to result
      > Multiply 0.6400000000139698 with 2.  Since 1.2800000000279397 is >= 1. then add 1 to result
      > Multiply 0.2800000000279397 with 2.  Since 0.5600000000558794 is < 1. then add 0 to result
      > Multiply 0.5600000000558794 with 2.  Since 1.1200000001117587 is >= 1. then add 1 to result
      > Multiply 0.12000000011175871 with 2.     Since 0.24000000022351742 is < 1. then add 0 to result
      > Multiply 0.24000000022351742 with 2.     Since 0.48000000044703484 is < 1. then add 0 to result
      > Multiply 0.48000000044703484 with 2.     Since 0.9600000008940697 is < 1. then add 0 to result
      > Multiply 0.9600000008940697 with 2.  Since 1.9200000017881393 is >= 1. then add 1 to result
      > Multiply 0.9200000017881393 with 2.  Since 1.8400000035762787 is >= 1. then add 1 to result
      > Multiply 0.8400000035762787 with 2.  Since 1.6800000071525574 is >= 1. then add 1 to result
      > Multiply 0.6800000071525574 with 2.  Since 1.3600000143051147 is >= 1. then add 1 to result
      > Multiply 0.36000001430511475 with 2.     Since 0.7200000286102295 is < 1. then add 0 to result
      > Multiply 0.7200000286102295 with 2.  Since 1.440000057220459 is >= 1. then add 1 to result
      > Multiply 0.440000057220459 with 2.   Since 0.880000114440918 is < 1. then add 0 to result
      > Multiply 0.880000114440918 with 2.   Since 1.760000228881836 is >= 1. then add 1 to result
      > Multiply 0.7600002288818359 with 2.  Since 1.5200004577636719 is >= 1. then add 1 to result
      > Multiply 0.5200004577636719 with 2.  Since 1.0400009155273438 is >= 1. then add 1 to result
      > Multiply 0.04000091552734375 with 2.     Since 0.0800018310546875 is < 1. then add 0 to result
      > Multiply 0.0800018310546875 with 2.  Since 0.160003662109375 is < 1. then add 0 to result
      > Multiply 0.160003662109375 with 2.   Since 0.32000732421875 is < 1. then add 0 to result
      > Multiply 0.32000732421875 with 2.    Since 0.6400146484375 is < 1. then add 0 to result
      > Multiply 0.6400146484375 with 2.     Since 1.280029296875 is >= 1. then add 1 to result
      > Multiply 0.280029296875 with 2.  Since 0.56005859375 is < 1. then add 0 to result
      > Multiply 0.56005859375 with 2.   Since 1.1201171875 is >= 1. then add 1 to result
      > Multiply 0.1201171875 with 2.    Since 0.240234375 is < 1. then add 0 to result
      > Multiply 0.240234375 with 2.     Since 0.48046875 is < 1. then add 0 to result
      > Multiply 0.48046875 with 2.  Since 0.9609375 is < 1. then add 0 to result
      > Multiply 0.9609375 with 2.   Since 1.921875 is >= 1. then add 1 to result
      > Multiply 0.921875 with 2.    Since 1.84375 is >= 1. then add 1 to result
      > Multiply 0.84375 with 2.     Since 1.6875 is >= 1. then add 1 to result
      > Multiply 0.6875 with 2.  Since 1.375 is >= 1. then add 1 to result
      > Multiply 0.375 with 2.   Since 0.75 is < 1. then add 0 to result
      > Multiply 0.75 with 2.    Since 1.5 is >= 1. then add 1 to result
      > Multiply 0.5 with 2.     Since 1.0 is >= 1. then add 1 to result
      > This is equal to 1, so, stop calculating
   0.11500000000000021 of decimal is .0001110101110000101000111101011100001010001111011 in binary
   so, 2.115 in binary is 10.0001110101110000101000111101011100001010001111011
2.115 in simple binary => 10.0001110101110000101000111101011100001010001111011
so, 2.115 in normal binary is 10.0001110101110000101000111101011100001010001111011 => 1.00001110101110000101 * 2^1

single precision:
--------------------
sign bit is 0(+ve)
exp bits are (127+1=128) => 10000000
   Divide 128 successively by 2 until the quotient is 0
      > 128/2 = 64, remainder is 0
      > 64/2 = 32, remainder is 0
      > 32/2 = 16, remainder is 0
      > 16/2 = 8, remainder is 0
      > 8/2 = 4, remainder is 0
      > 4/2 = 2, remainder is 0
      > 2/2 = 1, remainder is 0
      > 1/2 = 0, remainder is 1
   Read remainders from the bottom to top as 10000000
   So, 128 of decimal is 10000000 in binary
frac bits are 00001110101110000101000

so, 2.115 in single-precision format is 0 10000000 00001110101110000101000
in hexadecimal it is 0x40075C28

Related Solutions

Convert -10.5 single-precision floating point binary format. Please show every single detail for upvote. Please do...
Convert -10.5 single-precision floating point binary format. Please show every single detail for upvote. Please do not answer otherwise.
Convert 0xCD001234 from IEEE-754 hexadecimal to single-precision floating point format. Please show every single detail for...
Convert 0xCD001234 from IEEE-754 hexadecimal to single-precision floating point format. Please show every single detail for upvote. Please do not answer otherwise.
Convert 0xCD001234 from IEEE-754 hexadecimal to single-precision floating point format. Please show every single detail for...
Convert 0xCD001234 from IEEE-754 hexadecimal to single-precision floating point format. Please show every single detail for upvote. Please do not answer otherwise.
Please convert 2.75 into IEEE-754 format. Provide every single detail for upvote
Please convert 2.75 into IEEE-754 format. Provide every single detail for upvote
Convert 1101.11011101 x 223 to IEEE Standard 754 for single-precision floating-point binary format. Convert the IEEE...
Convert 1101.11011101 x 223 to IEEE Standard 754 for single-precision floating-point binary format. Convert the IEEE Standard 754 number 11001010100011010101000000000000 to its decimal equivalent.
A) Convert 1101.11011101 x 223 to IEEE Standard 754 for single precision floating-point binary format. B)...
A) Convert 1101.11011101 x 223 to IEEE Standard 754 for single precision floating-point binary format. B) Convert the IEEE Standard 754 number 11001010100011010101000000000000 to its decimal equivalent.  
Q1.Convert C46C000016 into a 32-bit single-precision IEEE floating-point binary number.
Q1.Convert C46C000016 into a 32-bit single-precision IEEE floating-point binary number.
Convert 103.375 into double precision floating format show all steps and explanations
Convert 103.375 into double precision floating format show all steps and explanations
Convert -99.999 into double precision floating format show all steps and explanations
Convert -99.999 into double precision floating format show all steps and explanations
Convert 103.375 into double precision floating format show all steps and explanations
Convert 103.375 into double precision floating format show all steps and explanations
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT