In: Statistics and Probability
In a large population, 46% of the households own VCR’s. A SRS of 100 households is to be contacted and asked if they own a VCR.
a. Let p^ be the sample proportion who say they own a VCR. find the mean of the sampling distribution of the sample proportion
b. Let p^ be the sample proportion who say they own a VCR. Find the standard deviation of the sampling distribution of the sample proportion
c. Let p^ be the sample proportion who say they own a VCR. Why is the sampling distribution of p^ approximately normal
d. What is the probability that more than 60 will own VCRs?
e. Let p^ be the sample proportion who say they own a VCR. If we decrease the sample size from 100 to 50 that would multiply the standard deviation of the sampling distribution by a factor of:
a. Let p^ be the sample proportion who say they own a VCR. find the mean of the sampling distribution of the sample proportion
The mean of the sampling distribution of the sample proportion = 0.46
b. Let p^ be the sample proportion who say they own a VCR. Find the standard deviation of the sampling distribution of the sample proportion
The standard deviation of the sampling distribution of the sample proportion = sqrt((0.46*(1-0.46))/100) = 0.045
c. Let p^ be the sample proportion who say they own a VCR. Why is the sampling distribution of p^ approximately normal
np = 100*0.46 = 46 >= 10
n(1-p) = 100*.54 = 54 >= 10
Thus, the sampling distribution of p^ is approximately normal.
d. What is the probability that more than 60 will own VCRs?
The test statistic = 0.60-0.46/sqrt(0.46*(1-0.46)/100) = 2.81
The probability is 0.0025.
e. Let p^ be the sample proportion who say they own a VCR. If we decrease the sample size from 100 to 50 that would multiply the standard deviation of the sampling distribution by a factor of:
The standard deviation of the sampling distribution will be multiplied by a factor of 4.