In: Statistics and Probability
An SRS of 100 flights of a large airline (call this
airline 1) showed that 64 were on time. An SRS of 100 flights of
another large airline (call this airline 2) showed that 80 were on
time. Let p1 and
p2 be the proportion
of all flights that are on time for these two airlines.
Reference: Ref 8-10
You wish to determine whether there is evidence of a difference in the on-time rate for the two airlines? To determine this, you test the hypotheses H0: p1 = p2, Ha: p1 ? p2. Using a 5% significance level, the conclusion to be drawn is that there is: |
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From the given information,
Let, n1 = number of flights of airline 1 = 100 and n2 = number of flights of airline 1 = 100
p1 = sample proportion of on-time flights outoff 100 flights of airline 1 = 64/100 = 0.64
p2 = sample proportion of on-time flights outoff 100 flights of airline 2 = 80/100 = 0.80
Let, P1 = population proportion of on-time flights of airline 1 and
P2 = population proportion of on-time flights of airline 2
We have to test the hypothesis H0 : P1 = P2 against H1 : P1 P2
Therefore,
Therefore, the test statistic is
Therefore, the value of the test statistic is 2.5198.
Level of significance = 0.05
Therefore, Z0.025 = 1.96
Since |z| = 2.5198 > Z0.025 = 1.96, we reject the null hypothesis at 5% level of significance and conclude that there is statistically significant evidence that the on-time rate is different for the two airlines at 5% level of significance.