A basketball player makes a jump shot. The 0.530-kg ball is released at a height of...

A basketball player makes a jump shot. The 0.530-kg ball is released at a height of 1.90 m above the floor with a speed of 7.12 m/s. The ball goes through the net 3.02 m above the floor at a speed of 4.24 m/s. What is the work done on the ball by air resistance, a nonconservative force?

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A basketball player makes a jump shot. The 0.600 kg ball is released at a height of 2.00 m above the floor with a speed of 7.80 m/s. The ball goes through the net 3.10 m above the floor at a speed of 3.30 m/s. What is the work done on the ball by air resistance, a nonconservative force?

Answer:

change in KE = work done by gravity + work done byair resistance

final K - initial K = - mg ?h + work by air resistance

(1/2) * 0.6 * 3.30² - (1/2) * 0.6 * 7.70² = - 0.600 * 9.80* (3.10 - 2.00) + work by air

3.267 - 17.787 = 5.292 + work by air

work by air = -19.812 Joules

genius_generous answered 11 hours ago

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