Question

In: Chemistry

PLEASE explain Spectrophotometry and what is soo important about 400nm PLEASE explain how absorbance and beer's...

PLEASE explain Spectrophotometry and what is soo important about 400nm

PLEASE explain how absorbance and beer's law relate

Relate Beer’s law to the equation of a line on a standard curve.

Why is the line forced through zero on the standard curve?

What does the R2 value for the graph says about the experiment?

Solutions

Expert Solution

Spectrophotomtery: Spectrophotometry is a method to measure how much a chemical substance absorbs light by measuring the intensity of light as a beam of light passes through sample solution. The basic principle is that each compound absorbs or transmits light over a certain range of wavelength. This measurement can also be used to measure the amount of a known chemical substance. A spectrophotometer is an instrument that measures the amount of photons (the intensity of light) absorbed after it passes through sample solution. With the spectrophotometer, the amount of a known chemical substance (concentrations) can also be determined by measuring the intensity of light detected.

400nm is important: 400nm is at the verge of both ultraviolet range (185 - 400 nm) and visible range (400 - 700 nm) of electromagnetic radiation spectrum.This helps in analyzing a great number of samples.

Relation of absorbance and Beer's Law: Beer-Lambert Law (also known as Beer's Law) states that there is a linear relationship between the absorbance and the concentration of a sample. For this reason, Beer's Law can only be applied when there is a linear relationship. Beer's Law is written as:

A=?lc

where A is the measure of absorbance (no units), ? is the molar extinction coefficient or molar absorptivity (or absorption coefficient), l is the path length, and c is the concentration. The molar extinction coefficient is given as a constant and varies for each molecule. Since absorbance does not carry any units, the units for ? must cancel out the units of length and concentration. As a result, ? has the units: L


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