Code1: #include int main(){ int res1, res2, res; printf("\nEnter Value of Each Resistance...

Code1:

#include
int main(){
    int res1, res2, res;

   printf("\nEnter Value of Each Resistance 1: ");
   scanf("%d", &res1);
   printf("\nEnter Value of Each Resistance 2: ");
   scanf("%d", &res2);
   res = res1+res2;
   printf("\nEquivalent Series Resistance : %d Kohm\n", res);

   return (0);
}

----------------------------------------------------------------------------------------------------------

Code2:

#include
int main(){
    int res1, res2, res;

   printf("\nEnter Value of Each Resistance 1: ");
   scanf("%d", &res1);
   printf("\nEnter Value of Each Resistance 2: ");
   scanf("%d", &res2);
   res = (res1*res2)/(res1+res2);
   printf("\nEquivalent Parellel Resistance : %d Kohm\n", res);

   return (0);
}

Take the two programs and combine them into a single program(using c not c++) that uses an if and else statement to calculate R total either in series or parallel based on the users preference (ask the users which way they want the resistance calculated).

Expert Solution

main.c

#include<stdio.h>
int main(){
    int res1, res2, res,start;

   printf("Enter Value of Each Resistance 1: ");
   scanf("%d", &res1);
   printf("\nEnter Value of Each Resistance 2: ");
   scanf("%d", &res2);

   printf("\nEnter 0 to quite\nEnter 1 for series circuit\nEnter 2 for parallel circuit: ");
   scanf("%d",&start);

if (start==0){
    return 0;
}
else if (start==1){
    res = res1+res2;
   printf("\nEquivalent Series Resistance : %d Kohm\n", res);
}
else if (start==2){
res = (res1*res2)/(res1+res2);
   printf("\nEquivalent Parellel Resistance : %d Kohm\n", res);
}
else {
    printf("Error!");}
   return (0);
}

Output:-

Enter Value of Each Resistance 1: 100
Enter Value of Each Resistance 2: 200
Enter 0 to quite
Enter 1 for series circuit
Enter 2 for parallel circuit: 2
Equivalent Parellel Resistance : 66 Koh

venereology answered 8 months ago

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