Can you please write a pseudocode for the following: #include <stdio.h> int main(){ printf("Welcome to...

Can you please write a pseudocode for the following:

#include <stdio.h>
int main(){
   printf("Welcome to my Command-Line Calculator (CLC)\n");
   printf("Developer: Your name will come here\n");
   printf("Version: 1\n");
   printf("Date: Development data Will come here\n");
   printf("----------------------------------------------------------\n\n");
   //choice stores users input
   char choice;
   //to store numbers
   int val1,val2;
   //to store operator
   char operation;
   //flag which leths the loop iterate
   //the loop will break once the flag is set to 0
   int flag=1;
   printf("Select one of the following items: \n");
   printf("B) - Binary Mathematical Operations, such as addition and subtraction.\n");
   printf("U) - Unary Mathematical operations, such as square root, and log.\n");
   printf("A) - Advances Mathematical Operations, using variables, arrays.\n");
   printf("V) - Define variables and assign them values.\n");
   printf("E) - Exit\n");
   //taking user input for choice
   scanf(" %c",&choice);
   //do while loop
   do{
       //switch case
   switch(choice){
       case 'B':
           printf("Please enter the first number:\n");
           scanf("%d",&val1);
           printf("Please enter the operation (+ , - , * , / ):\n");
           scanf(" %c",&operation);
           printf("Please enter the second number:\n");
           scanf("%d",&val2);
           switch (operation){
               case '+':
                   printf("The result is %d \n",(val1+val2));
                   break;
               case '-':
                   printf("The result is %d \n",(val1-val2));
                   break;
               case '*':
                   printf("The result is %d \n",(val1*val2));
                   break;
               case '/':
                   printf("The result is %d \n",(val1/val2));
                   break;
               //if any other input is entered
               default:
                   printf("Invalid operator\n");
               }
           //asking the user for input as the operation ended
           printf("Please select your option ( B , U , A , E , V)\n");
           scanf(" %c",&choice);
           break;

       case 'U':
           printf("Sorry, at this time I don't have enough knowledge to serve you in this category\n");
           //asking the user for input as the operation ended
           printf("Please select your option ( B , U , A , E , V)\n");
           scanf(" %c",&choice);
           break;
       case 'A':
           printf("Sorry, at this time I don't have enough knowledge to serve you in this category\n");
           //asking the user for input as the operation ended
           printf("Please select your option ( B , U , A , E , V)\n");
           scanf(" %c",&choice);
           break;
       case 'V':
           printf("Sorry, at this time I don't have enough knowledge to serve you in this category\n");
           //asking the user for input as the operation ended
           printf("Please select your option ( B , U , A , E , V)\n");
           scanf(" %c",&choice);
           break;
       case 'E':
           //if user enters E flag is set to 0, so that the loop will break
           flag=0;
           printf("Thanks for using my Simple Calculator. Hope o see you soon again, Goodbye!\n");
           break;
       default:
           printf("Invalid input");
           printf("Please select your option ( B , U , A , E , V)\n");
           scanf(" %c",&choice);
           }

   }while(flag);


}

Expert Solution

PseudoCode:

PseudoCode is an artificial and informal language that helps programmers develop algorithms.It is a "text-based" detail design tool.It is intended for human reading rather than machine.

PseudoCode for the given program is:

venereology answered 2 years ago

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