Question

Two Systems 80 Km apart are communicating through a direct Metallic cable (note: signal speed is 2 x 10^8 m/s). The data is in the form of 60 KB packets with transmission rate 1M bps. Calculate the following:

1. Data transmission time per packet.
2. Propagation delay.
3. bit duration.
4. Bit length.
5. Number of bits in the cable between the sender and receive

Answer 1

Answer:-

Data transmission time per packet= packet size/transmission rate.

                                                    =(60*2^10*2^3 bit)/(10^6 bps) =0.49152 s

Propagation delay=distance between two device/propagation speed

                           =(80*1000m)/(2*10^8 m/s)=0.0004 s=0.4ms

Number of bits in the cable between the sender and receive (capacity)=Transmission speed*propagation delay

                                                                                                  =1Mbps*0.0004 s

                                                                                                    =10^6*0.0004=400 bits