In: Statistics and Probability
Externalizers and Internalizers are two categories of personality types in a personality theory by Rotter. A large group of people at a PTA meeting were given a brief personality test and then classified as lower, middle, or upper class. Test to see if there is a relationship between SES and Externalizers and Internalizers. Write out your results and conclusions. Must show all work including the expected frequencies, chi square calculations, as well as LaTeX: \phi ? df and critical value for credit.
Lower |
Middle |
Upper |
|
Internalizers |
8 |
36 |
12 |
Externalizers |
18 |
21 |
2 |
Null Hypothesis H0: The personality types(Externalizers and Internalizers ) are independent of classes(lower, middle, or upper).
Alternative Hypothesis H1: The personality types(Externalizers and Internalizers ) are depends on classes(lower, middle, or upper).
Under H0, the expected frequencies are
(Obs. Freq.) | (Exp. Freq.) | |||||||
Lower | Middle | Upper | Total | Lower | Middle | Upper | Total | |
Internalizers | 8 | 36 | 12 | 56 | 15.01 | 32.91 | 8.08 | 56.00 |
Externalizers | 18 | 21 | 2 | 41 | 10.99 | 24.09 | 5.92 | 41.00 |
Total | 26 | 57 | 14 | 97 | 26 | 57 | 14 | 97.00 |
Calculations For Chi Square | ||||||||
Obs freq( O ) | Exp. Freq. ( E ) | (O-E)^2/E | ||||||
8 | 15.01 | 3.274 | ||||||
36 | 32.91 | 0.290 | ||||||
12 | 8.08 | 1.902 | ||||||
18 | 10.99 | 4.471 | ||||||
21 | 24.09 | 0.396 | ||||||
2 | 5.92 | 2.596 | ||||||
Total | 97 | 97 | 12.929 |
Under H0, the test statistic is
Degrees of freedom = (r-1)*(c-1) = (2-1)*(3-1)= 2
The critical value of Chi square for 2 df at 5% significance level is 5.991
The P-Value is 0.0016
Since p value is less than significance level, REject H0.
Hence , the personality types(Externalizers and Internalizers ) are depends on classes(lower, middle, or upper).