In: Statistics and Probability
A drug company is advertising that its snore-curing product has a success rate of at least 90%. A doctor has been prescribing the product to his customers, however she’s disap- pointed with the results. She decides to do an experiment on a random sample of 50 snorers. She puts them on a course to use the product in 2 weeks. After that, she calls them back to see whether the snoring has stopped. The results were: 42 stopped snoring and the rest still had it. Does the doctor has sufficient evidence to claim that the drug company’s advertisement was misleading at 5% significance level?
1. Ho: p (= ; <= ; >=) 0.9
Ha: p (< > ; > ; <) 0.9
2. Statistical test: (z / t) test
3. Level of significance (be careful as to one-tailed or two-tailed)
4. Set up critical values (Write the value in the box, include "-" sign if negative, if two values, just write the positive one)
5. Gather sample data: p_hat = ; n = 50
6. Calculate test statistic (write your answer correct to 2 decimal places)
6*. The p-value of the test is
7. Make statistical conclusion: (Reject / Do not reject) the null hypothesis. There is (sufficient/insufficient) evidence that the the drug company's advertising was misleading at 5% level of significance.