Question

In Python write a program that prompts the user for a file name, make sure the file exists and if it does reads through the file, count the number of times each word appears and then output the word count in a sorted order from high to low.

The program should:

• Display a message stating its goal
• Prompt the user to enter a file name
• Check that the file can be opened and if not ask the user to try again (hint: use the try/except structure)
• Count the number of times each word appears in the file, regardless if in lowercase or uppercase (hint: use dictionaries and the lower() function)
• Display the word count in order from high to low
• If a few words have the same count, sort the display in an alphabetic order
• For example, for the attached file NYT2.txt, the top five words in the output should be

the - 7

in - 6

to - 5

and - 4

of - 4

Remember:

• DO NOT use more advanced functions than needed.
• Make sure to include comments that explain all your steps (starts with #).
• Run the program a few times to make sure it executes and meets all the requirements.

NYT2.txt file below:

Fact-Checking Trump’s Orlando Rally: Russia, the Wall and Tax Cuts
President Trump delivered remarks in Florida in a formal start to his re-election effort.
Deutsche Bank Faces Criminal Investigation for Potential Money-Laundering Lapses        
Federal authorities are focused on whether the bank complied with anti-money-laundering laws, including in its review of transactions linked to Jared Kushner.
Five NY1 Anchorwomen Sue Cable Channel for Age and Gender Discrimination
The women, including Roma Torre, say their careers were derailed after Charter Communications bought New York’s hometown news station in 2016.
Hypersonic Missiles Are Unstoppable. And They’re Starting a New Global Arms Race.
The new weapons — which could travel at more than 15 times the speed of sound with terrifying accuracy — threaten to change the nature of warfare.
Nxivm’s Keith Raniere Convicted in Trial Exposing Sex Cult’s Inner Workings
Mr. Raniere set up a harem of sexual “slaves” who were branded with his initials and kept in line by blackmail.
Jamal Khashoggi Was My Fiancé. His Killers Are Roaming Free.
Washington hasn’t done enough to bring the murdered Saudi columnist’s killers to justice.

Answer 1

Hi,

The following is the code to print the frequency of words in the file.

Please ensure you create the nyt2.txt (or similar) file in current folder or any other folder and provide as input to the program.

#File: filewordcount.py

while True:
try:
#Get the name of the file to parse from the user
file_name = input("Enter the file name: ")

#Open the file and hold reference to the file
file = open(file_name)

#Dictionary to hold the count of each word in the file
word_count_dict = {}

#Read the file and spli the line into words
words = file.read().split()

#iterate each word in the list
for word in words:

#Check if the word is already in the dictionary, else initialize
if word.lower() not in word_count_dict:
word_count_dict[word.lower()] = 1
else:
#If word already exists in the dictionary, increment the counter
word_count_dict[word.lower()] += 1
  
#Sort the dictionary based on the values in descending order
sorted_word_count_dict = [(key, word_count_dict[key]) for key in sorted(word_count_dict, key=word_count_dict.get, reverse=True)]

#Get the max frequency from the sorted list
max_count = sorted_word_count_dict[0][1]

#Iterate from the max counter value to 1
for v in range(max_count, 0, -1):

#Find the words that have the same value as "v"
keys_same_value = [key for(key, value) in sorted_word_count_dict if value == v]

#If more than one word has same frequency, sort the words and display them
if len(keys_same_value) > 1:
sorted_keys_same_value = sorted(keys_same_value)
for i in range(len(sorted_keys_same_value)):
print(sorted_keys_same_value[i] + " : " + str(v))
else:   
#If there is only one word with same frequency, just display it
print( keys_same_value[0] + " : " + str(v))
  
break

except Exception as ex:
print("Error: Unable to read the file. Try again")
print(ex)
  

  

  
  
### Output