Question

Write a program that prompts the user for a file name, make sure the file exists and if it does reads through the file, count the number of times each word appears and then output the word count in a sorted order from high to low.

The program should:

• Display a message stating its goal
• Prompt the user to enter a file name
• Check that the file can be opened and if not ask the user to try again (hint: use the try/except structure)
• Count the number of times each word appears in the file, regardless if in lowercase or uppercase (hint: use dictionaries and the lower() function)
• Display the word count in order from high to low
• Bonus: if a few words have the same count, sort the display in an alphabetic order
• For example, for the attached file NYT2.txt, the top five words in the output should be

the - 7

in - 6

to - 5

and - 4

of - 4

Using Python as program language

Answer 1

Code:-

import re #importing library for splitting purpose
print("Printing the words in descending order based on frequency of the word in the file") #printing
while(True): #loop until user enters valid file name
filename=input("Enter filename: ") #Asking user to enter file name and taking filename from user
try:
file=open(filename,"r") #opening file in read mode
break; #if no exception
except: #if invalid filename
print("Invalid Filename Enter Again") #Asking user enter again
words=re.split('; |, |\*|\n|\s', file.read().lower()) #making all words to lowercase letters and splitting the text by(; , \n \s)
file.close() #closing the file
#here I want to sort the list for words in alphabetical order
words.sort() #sort the words list
frequency={} #declaring frequency dictionary
for i in words: #traverse through all the words in words list
if i not in frequency: #if word is not present in dictionary
frequency[i]= 0 #initiate the value with 0
frequency[i]+=1 #increment the count value
dictlist=list(frequency.items()) #here make dictionary to list for sorting purpose
for i in range(len(dictlist)-1, -1, -1): #bubble sort to sort the list using values
for j in range(i):
if dictlist[j][1] < dictlist[j+1][1]:
dictlist[j], dictlist[j+1] = dictlist[j+1], dictlist[j] #swapping
frequency=dict(dictlist) #make updatedlist to dictionary
for i in frequency:
print(i,"-",frequency[i]) #printing key along with value

Code Screenshot:-

OUTPUT:-