Answer
Problem Statement
- There
are 3 machine operators in a manufacturing factory.
- Every
day, each operator works for a single shift of 7.5
hours.
- The
factory operates 5 days a week.
Part a)
Last
month, in the first week (Week 1), the factory arranged overtime of
1 hours on 4 days for 2 machine operators. What is the utilization
of operators in Week 1?
Answer –
- 3
machine operator works in a manufacturing factory.
- Per
week total no of hours worked = No of operators * No of days in a
week worked * No of hours per day worked.
- Implies
per week total no of hours worked = 3 * 5 *7.5 hours
- Hence,
(planned hours of work)/ per week total no of hours worked =
112.5 hours per week , planned capacity per
week
As per
part a)
- Last
month, in the first week (Week 1), the factory arranged overtime of
1 hours on 4 days for 2 machine operators.
- therefore, extra hours
worked = 2* 1 *4 = 8 hours in Week 1
- Hence
Actual total hours worked = 112.5 + 8 = 120.5 hours in week
1
Hence, utilization in week
1
= Actual hours worked / Planned hours of work
= 120.5 / 112.5 = 1.0711 or
107.11%
Part b)
Because
of the overtime in Week 1, there was no more overtime in Week 2.
One of the operators even idled for 3 hours in 1 workday without
anything to do. What is the utilization of operators in Week
2?
Answer –
- So,
normal working hours per week in week 2 = 112.5 hours
- Idle
hours for 1 operator in week 2 = 3 hours for 1 day.
- Hence,
net hours worked in week 2 = normal working hours per week in week
2 - Idle hours for 1 operator in week 2
- =
112.5-3 = 109.5 hours per week
- Utilization of
operators in week 2
= Actual
hours worked / Planned hours of work
= net
hours worked in week 2 / normal working hours per week in week
2
=
109.5/112.5
= 0.9733 or 97.33%