Question

at 1000degrees C the value of equilibrium constant for the reaction below is 1.62. how many moles of each compound will there be at equilibrium if 1 mole of h2, 2 moles of co2, and 3 moles of co are placed in a 10 liter tank and heated to 1000 C? H2 (g) +aCO2 (g)-----H2O(g) + CO(g)

Answer 1

Solution :-

Balanced reaction equation

H2    + CO2     ------ > H2     + CO

Initial moles

[H2] =1 mol

[CO2] = 2 mol

[CO] = 3 mol

Kc =1.62

Lets write the ICE table

H2    + CO2     ------ > H20     + CO

1       2                      0                3

-x          -x                   +x            +x

1-x       2-x                  x             3+x

Kc= [H2O][CO]/[H2][CO2]

1.62 = [x][3+x]/[1-x][2-x]

1.62* [1-x][2-x] = [x][3+x]

Solving for x we get

x=0.427 mol

So at the equilibrium moles of each gas are as follows

[H2]eq = 1-x = 1-0.427 = 0.573 mol

[CO2]eq = 2-x =2-0.427 = 1.573 mol

[H2O]eq =x =0.427 mol

[CO]eq = 3+x = 3+0.427 = 3.427 mol