Question

write a program which will prompt an array of 12 integers then print the array as an array of 4 columns on 3 rows

Answer 1

/* First we will store these 12 integers in an array . After this we will create a two dimensional array of size 3 x 4 and then print the content of the 2 D array */

/*
1. Create a 1 dimensional array and insert any 12 elements into it.
2. create a dynamic 2 dimensional array of size 3 x 4
3. insert content of previous array into the dynamic array using
   array2d[i][j]=array1d[(j*row)+i]
4. print content of 2 D array two loops

if random numbers inserted into original array is :
   83 86 77 15 93 35 86 92 49 21 62 27
then ,its output will be like :
   83 15 86 21
   86 93 92 62
   77 35 49 27
  
   4 columns and 3 rows
*/

/* c++ code of the above algorithm */
#include<bits/stdc++.h>
using namespace std;

int main()
{
   int arr1d[12];
   for(int i=0;i<12;i++)             // inserting any random no (0 to 99)
       arr1d[i]=rand()%100;           // into 1 D array
// you can take any integer values
   for(int i=0;i<12;i++)
       cout<<arr1d[i]<<" ";           //checking content of 1 D array
   cout<<endl;
  
   int row=3, column=4;               // forming a dynamic 2 D array of
   int *array2d[row];                   // given size(standard approach)
   for(int i=0;i<row;i++)
       array2d[i]=(int*)malloc(column*sizeof(int));
  
   for(int i=0;i<row;i++)               // copying contents from 1 D array
   {
       for(int j=0;j<column;j++)      
           array2d[i][j]=arr1d[(j*row)+i];
                                       // array2d[i][j]=ith row and jth column
   }
   for(int i=0;i<row;i++)               // Displaying contents of 2 D array
   {  
       for(int j=0;j<column;j++)
           cout<<array2d[i][j]<<" ";
       cout<<endl;
   }
   return(0);
}