Question

Write a PYTHON program that uses a while loop to prompt for 5 integers.

If the number is equal to 99, display "Ninety-nine", otherwise display "no-match".

If the number is equal to 75, display "Seventy-five", otherwise display "no-match".

Answer 1

After reading the question, I understood that there can by many different interpretations of this program. There can be a program that prints ‘Ninety-nine’ if the input is 99 and ‘no-match’ if it is not, and will print ‘Seventy-five’ if input is 75 else ‘no-match’ in a way that there will be two lines of output in every iteration, one for each check. There can also be another way like if the input is 99, ‘Ninety-nine’ is printed, ‘Seventy-five’ if it is 75, or ‘no-match’ if it is neither 75 nor 95. Here is the completed code for both type implementations. Take whichever you want. (Choose either first version or second version, not both) Comments are included, go through it, learn how things work and let me know if you have any doubts or if you need anything to change. If you are satisfied with the solution, please rate the answer. Thanks

Note: Please maintain proper code spacing (indentation), just copy the code part and paste it in your compiler/IDE directly, no modifications required.

#code

'''
First version of the program. This will prompt and read 5 numbers from input,
if the number is 99, 'Ninety-nine' will be printed, otherwise 'no-match' will be
printed. Similarly, if the number is 75, 'Seventy-five' is printed, else
'no-match' is printed. So in an iteration if the input is 75, the output
will be like below

no-match
Seventy-five

and if the input is 95, the output will be like

Ninety-nine
no-match

and if the input is any other, like 34

no-match
no-match
'''

#initializing i to 0
i=0
#looping as long as i is less than 5
while i<5:
    #prompting and reading an integer
    num=int(input("Enter a number: "))
    #checking if number is 99
    if num==99:
        #printing 'Ninety-nine'
        print("Ninety-nine")
    else:
        #otherwise, printing 'no-match'
        print("no-match")
    # checking if number is 75
  if num == 75:
        # printing 'Seventy-five'
        print("Seventy-five")
    else:
        # otherwise, printing 'no-match'
        print("no-match")
    #updating i for next iteration
    i+=1

'''
Second version of the program. This will prompt and read 5 numbers from input,
if the number is 99, 'Ninety-nine' will be printed, otherwise if the number is 75,
'Seventy-five' is printed, else 'no-match' is printed. So in an iteration if the input is 75,
the output will be like below

Seventy-five

and if the input is 95, the output will be like

Ninety-nine

and if the input is any other, like 34

no-match
'''


#initializing i to 0
i=0
#looping as long as i is less than 5
while i<5:
    #prompting and reading an integer
    num=int(input("Enter a number: "))
    #checking if number is 99
    if num==99:
        #printing 'Ninety-nine'
        print("Ninety-nine")
    #otherwise checking if number is 75
    elif num == 75:
        # printing 'Seventy-five'
        print("Seventy-five")
    else:
        # otherwise, printing 'no-match'
        print("no-match")
    #updating i for next iteration
    i+=1