Question

WORKSHEET 1- answers. i need explanation and wrok shown for each questions.

1) A 2) C 3) E 4) E 5) E 6) E 7) D 8) E 9) B 10) E 11) D 12) C 13) D 14) D 15) B 16) D

http://east.cherryhill.k12.nj.us/Summer_Assignments/pdfs/c01ws01.pdf

Answer 1

1) Ans: (A) Fe valency state having 3d⁶4s² configaration.

in the exited state it is 3d⁵4s¹4p²

   in Fe⁺² state3d⁵4s¹.

   The configaration resebles with the H atom like S¹.

2)Ans: (C) it having Argon configuration. (K= 1s²2s²2p⁶3s²3p64s¹

   K⁺ configaration is 1s²2s²2p⁶3s²3p6 is matches with the Ar configaration.

3)Ans: Hg+ configaration: [Xe] 4f¹⁴ 5d¹⁰ 6s¹.

4)Ans: Isoelectonic means same electron configuration.

Au (gold) and Hg+ are isoelectonic. The configuration is [Xe] 4f¹⁴ 5d¹⁰ 6s¹.

5) (E) The no. of electons is more than the Protans the net charge is negative.

6) (E) They are Isobars cotaines the same total of p+n (mass no is same).

7) physical property alway depends on the molecular weight (mass).

The reaction depends(chemical property) on the elecron configuration.

8) Isotopes are variants of a particular chemical element which differ in neutron number, although all isotopes of a given element have the same number of protons in each atom.

9) n=4 l=1 that means 4p orbital 3 elecrons in the orbital (l=0 means S orbital, l=1 means P orbital)

10) The d-orbital starts from the n=3 that means 3d.

11)Atomic number equal to the protans number and electrons number.

12)mass no. depends on the total no. of protans and neutrons (p+n).

13) outer shell is having 3s²3p¹ configuration

in exited state 3s¹3px¹ and 3py¹

14) Cr configuration[Ar] 3d5 4s1

Cr⁺³ having configuration [Ar] 3d2 4s1 means 3 lone pair electrons (para magnetic).

15) (B) mass=protans+neutrans (protans no.=electrons)

93=42+n

neutrans= 51

16) (B) Na atomic no is 11 that means having 11protans is equal to the 11 electrons.

Na+ is losing one electron means 10 electrons that is Ne configuration.