Question

(PYTHON)

prompt the user to enter a single-digit num and print that num as follow:

1) use loops

2) print num in words. Example: 5 is 'five'

3) the number of spaces that go back and forth should equal the num

if the user inputs 5, the program prints:

five

. . . . .five

five

. . . . . five

five

and 2 would be:

two

. .two

(the periods(.) are only for demonstration purposes. Don't include it in the actual output).

Answer 1

program with explanation (Python 3.7)

# python dictionary used to store key: value pair.
# Dictionaries are optimized to retrieve values when the key is known.
num2words = {1: 'One', 2: 'Two', 3: 'Three', 4: 'Four', 5: 'Five', 6: 'Six', 7: 'Seven', 8: 'Eight', 9: 'Nine'}

# function definition part
def number(Number):
  
# if condition: used to check number between 0 and 10
if (Number >= 1) and (Number <=9):
  
# Using the key retrieves the value from the dictionary
value= num2words[Number]
  
# Loop part : printing the number in its number of times
for x in range(Number):
print(value)
else:
# else part of the loop
print("Number Out Of Range")
  
# calls main() for continue this problem
main()

# main part part of the program
# when program runs it start from here
def main():
  
# Takes input from the user
num = eval(input("Please enter a number between 0 and 10: "))
  
# function calling part and pass value num
number(num)
  
# calling main() to start program
main()

code only(Python 3.7)

num2words = {1: 'One', 2: 'Two', 3: 'Three', 4: 'Four', 5: 'Five', 6: 'Six', 7: 'Seven', 8: 'Eight', 9: 'Nine'}
def number(Number):
if (Number >= 1) and (Number <=9):
value= num2words[Number]
for x in range(Number):
print(value)
else:
print("Number Out Of Range")
main()
def main():
num = eval(input("Please enter a number between 0 and 10: "))
number(num)
main()

output