Question

Answer using Jupyter Python #Prompt the user to enter a passing grade and store the value from #the input() into a variable. #Refer to the variable in problem 2 to complete the following: #Use the if statement to evaluate the only the first element in the #grades list using index notation. #If the grade is passing, display PASSED, otherwise display FAILED. """Problem 1d""" #Use the for statement to iterate on each element in the #grades list (from problem 1a) and displays each value. #Specifically, for each grade in the grades list, if the grade is #passing (referring to problem 1b), then display PASSED, otherwise display FAILED. """Problem 2a""" #Create a function that will evaluate if each grade in a list is considered #passing or failing. [hint: use the for statement and if...else together] #Store the total number of passing and failing grades in their own respective variables. #The function should return a dictionary with two key-value pairs where the keys are # the words PASSED and FAILED mapped to their total counts variable. """Problem 2b""" #Call the function and pass in the grades list (from problem 1a) as an argument.

Answer 1

As per your requirement, here is the Python code:

Rawcode:

#asking user to enter passing grade and storing it in variable

passing = int(input("Enter a passing grade: "))

#problem 1a

#creating grades list

grades = [20, 50, 43, 56, 67, 23, 96, 41, 85, 73, 43, 25, 43]

#Using the if statement to evaluate the only the first element in the #grades list using index notation.

if(grades[0] is passing):

    print("PASSED")

else:

    print("FAILED")

#problem 1b

#Using the for statement to iterate on each element in the #grades list (from problem 1a) and displays each value.

for i in grades:

    print(i)

    # if the grade is #passing (referring to problem 1b), then display PASSED

    if(i is passing):

        print("PASSED")

    #otherwise display FAILED.

    else:

        print("FAILED")

#Creating a function that will evaluate if each grade in a list is considered #passing or failing

def gradeCount(grades):

    #creating an empty dictionary

    countDict = dict()

    #initializing passed count

    passCount = 0

    #initializing failed count

    failCount = 0

    #looping through grades list

    for i in grades:

        #checking if they are passing

        if(i is passing):

            #then incrementing pass count

            passCount = passCount + 1

        #if it they are failed

        else:

            #then incrementing fail count

            failCount = failCount + 1

    #mapping passCount value to key PASSED

    countDict['PASSED'] = passCount

    #mapping failCount value to key FAILED

    countDict['FAILED'] = failCount

    #returns dictionary of count of both passed and failed

    return countDict

#Calling the function and pass in the grades list (from problem 1a) as an argument.

print(gradeCount(grades))

Here is the screenshots of source code:

Here is the screenshot of output:

Hope this helps you. Please feel free to ask if you still have any queries.

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