Question

In: Computer Science

Write a recursive function to check if a string whose each character is stored in a...

Write a recursive function to check if a string whose each character is stored in a separate node in a doubly linked list, is a palindrome. Use the code available from DoublyLinkedList.hpp on our Github.

//
// Doubly-linked list with 2 dummy nodes
//
#pragma once
#include <stdexcept>
template<typename T>
struct Node {
T data;
Node<T>* next;
Node<T>* prev;
Node() = delete; // Intentionally no default constructor
Node( const T & element ) : data( element ), next( nullptr ), prev( nullptr ) {}
};
template<typename T>
class DoublyLinkedList {
private:
Node<T>* head;
Node<T>* tail;
public:
// Constructors
DoublyLinkedList();
DoublyLinkedList(const DoublyLinkedList&);
DoublyLinkedList& operator=(const DoublyLinkedList&); // assignment operator
~DoublyLinkedList(); // destructor
// Getters / Setters
bool empty();
int size() = delete; // INTENTIONALLY NOT IMPLEMENTED !!
void append( const T& );
void prepend( const T& );
void insertAfter( Node<T>*, const T& );
void remove( Node<T>* );
void pop_front(); // remove element at front of list
void pop_back(); // remove element at back of list
T& front(); // return list's front element
T& back(); // return list's back element
void clear();
};
template<typename T>
DoublyLinkedList<T>::DoublyLinkedList() {
head = new Node<T>( T() ); // create dummy nodes
tail = new Node<T>( T() );
head->next = tail; // have them point to each other
tail->prev = head;
}
template<typename T>
bool DoublyLinkedList<T>::empty() {
return head->next == tail;
}
template<typename T>
void DoublyLinkedList<T>::append( const T& newData ) {
Node<T> * newNode = new Node<T>( newData ); // create new node
newNode->prev = tail->prev;
newNode->next = tail;
tail->prev->next = newNode;
tail->prev = newNode;
}
template<typename T>
void DoublyLinkedList<T>::prepend( const T& newData ) {
Node<T> * newNode = new Node<T>( newData ); // create new node
Node<T> * firstNode = head->next;
newNode->next = head->next;
newNode->prev = head;
head->next = newNode;
firstNode->prev = newNode;
}
template<typename T>
void DoublyLinkedList<T>::insertAfter(Node<T>* curNode, const T& newData) {
if (curNode == tail) {
// Can't insert after dummy tail
return;
}
// Construct new node
Node<T>* newNode = new Node<T>( newData );
Node<T>* sucNode = curNode->next;
newNode->next = sucNode;
newNode->prev = curNode;
curNode->next = newNode;
sucNode->prev = newNode;
}
template<typename T>
void DoublyLinkedList<T>::remove(Node<T>* curNode) {
if( empty() ) throw std::length_error( "empty list" );
if (curNode == head || curNode == tail) {
// Dummy nodes cannot be removed
return;
}
Node<T>* sucNode = curNode->next;
Node<T>* predNode = curNode->prev;
// Successor node is never null
sucNode->prev = predNode;
// Predecessor node is never null
predNode->next = sucNode;
}
template <typename T>
void DoublyLinkedList<T>::pop_front() {
remove(head->next);
}
template <typename T>
void DoublyLinkedList<T>::pop_back() {
remove(tail->prev);
}
template <typename T>
T& DoublyLinkedList<T>::front() {
if( empty() ) throw std::length_error( "empty list" );
return head->next->data;
}
template <typename T>
T& DoublyLinkedList<T>::back() {
if( empty() ) throw std::length_error( "empty list" );
return tail->prev->data;
}
template<typename T>
void DoublyLinkedList<T>::clear() {
while( !empty() )
pop_front();
}
template<typename T>
DoublyLinkedList<T>::~DoublyLinkedList() {
clear();
delete head; // remove the dummy nodes
delete tail;
}
template <typename T>
DoublyLinkedList<T>::DoublyLinkedList( const DoublyLinkedList<T> & original ) : DoublyLinkedList() {
// Walk the original list adding copies of the elements to this list maintaining order
for( Node<T> * position = original.head->next; position != original.tail; position = position->next ) {
append( position->data );
}
}
template <typename T>
DoublyLinkedList<T> & DoublyLinkedList<T>::operator=( const DoublyLinkedList<T> & rhs ) {
if( this != &rhs ) // avoid self assignment
{
// Release the contents of this list first
clear(); // An optimization might be possible by reusing already allocated nodes
// Walk the right hand side list adding copies of the elements to this list maintaining order
for( Node<T> * position = rhs.head->next; position != rhs.tail; position = position->next ) {
append( position->data );
}
}
return *this;

}

Think like, you are adding function/s to this class code. Also write a helper function.

A string is a palindrome if its reverse is the same as the original string. For e.g. “civic” is a palindrome. The function should return bool true or false.



b) Why do we have to write two functions for the above recursive implementation ? How many functions do we have to write for the singly linked list we created in Simple Singly Linked List Example.cpp code posted on Titanium ?


Solutions

Expert Solution

Function to check if a doubly linkedList is Palindrome or not

bool Palindrome(struct Node *left)

{

    if (left == NULL)

       return true;

  

    // Find rightmost node

    struct Node *right = left;

    while (right->next != NULL)

        right = right->next;

  

    while (left != right)

    {

        if (left->data != right->data)

            return false;

  

        left = left->next; // next is pointing to the next node

        right = right->prev; //prev is pointing to the previous node

    }

  

    return true;

}

2. A Double linked list usually has two links one for the next node, one for the previous node as compared to a singly linked list which has only one link to the next node, hence two functions have been written for double linked list


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