Question

C++, Write a function, noPunct, that would take a string, go through the string character by character, and push any character that is NOT a punctuation mark onto a stack but count the punctuation dropped. After going through the entire string, print the contents of the stack. Then print the number of punctuation dropped.

Hint: use ispunct() library function (returns true if character is punctuation)

Answer 1

Note: Variable names and object names are used arbitrarily. These can be changed according to the user's choice. Please refer to code snippets for a better understanding of comments and indentations.

IDE Used: Dev C++

Program Code

#include <iostream>
#include <string>
#include <ctype.h>
#include <bits/stdc++.h>

using namespace std;

// function that will take input string
// and display number of punction dropped
void noPunct(string inp_stg )
{
   // declare stack obkect
   stack <char> char_stack;
  
   // count number of punctuation
   int num_punc = 0;
  
   // check each character of the input string
   for(int itr = 0; itr < inp_stg.length(); itr++)
   {
       // check if character is a punctuation mark
       if(ispunct(inp_stg[itr]))
       {
           // if yes then increment punctuation counter
           num_punc++;
          
       }
      
       else
       {
           // if not then push the character to the stack
           char_stack.push(inp_stg[itr]);
       }
      
      
   }
  
   // show the content of the stack
   cout<<"\nContent of the stack\n";
   while (!char_stack.empty())
{
cout<<" "<<char_stack.top();
char_stack.pop();
}
  
// show the number of punctuation dropped
cout<<"\nNumber of punctuation marks dropped : "<<num_punc;
  
}

// main function
int main()
{
   // input string
   string inp_stg;
  
   // prompt user to input the string
   cout<<"Input string to read : ";
  
   // read the string
   getline(cin, inp_stg);
  
   // call the function
   noPunct(inp_stg);
  
   return 0;
}

Code Snippets

Sample Output