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The following data was reported on total Fe for four types of iron formation (1 =...

The following data was reported on total Fe for four types of iron formation (1 = carbonate, 2 = silicate, 3 = magnetite, 4 = hematite). 1: 20.7 28.1 27.8 27.0 28.1 25.2 25.3 27.1 20.5 31.8 2: 26.4 24.0 26.2 20.2 24.2 34.0 17.1 26.8 23.7 24.5 3: 29.9 34.0 27.5 29.4 27.9 26.2 29.9 29.5 30.0 35.7 4: 37.1 44.2 34.1 30.3 31.8 33.1 34.1 32.9 36.3 25.8 Carry out an analysis of variance F test at significance level 0.01. State the appropriate hypotheses. H0: μ1 = μ2 = μ3 = μ4 Ha: all four μi's are unequal H0: μ1 ≠ μ2 ≠ μ3 ≠ μ4 Ha: at least two μi's are equal H0: μ1 ≠ μ2 ≠ μ3 ≠ μ4 Ha: all four μi's are equal H0: μ1 = μ2 = μ3 = μ4 Ha: at least two μi's are unequal Summarize the results in an ANOVA table. (Round your answers two decimal places.) Source df Sum of Squares Mean Squares f Treatments Error Total Give the test statistic. (Round your answer to two decimal places.) f = What can be said about the P-value for the test? P-value > 0.100 0.050 < P-value < 0.100 0.010 < P-value < 0.050 0.001 < P-value < 0.010 P-value < 0.001 State the conclusion in the problem context. Reject H0. There is sufficient evidence to conclude that the total Fe differs for at least two of the four formations. Reject H0. There is insufficient evidence to conclude that the total Fe differs for the four formations. Fail to reject H0. There is insufficient evidence to conclude that the total Fe differs for the four formations. Fail to reject H0. There is sufficient evidence to conclude that the total Fe differs for at least two of the four formations. You may need to use the appropriate table in the Appendix of Tables to answer this question.

Solutions

Expert Solution

Answer:

The following data was reported on total Fe for four types of iron formation (1 = carbonate, 2 = silicate, 3 = magnetite, 4 = hematite).

1: 20.7 28.1 27.8 27.0 28.1 25.2 25.3 27.1 20.5 31.8

2: 26.4 24.0 26.2 20.2 24.2 34.0 17.1 26.8 23.7 24.5

3: 29.9 34.0 27.5 29.4 27.9 26.2 29.9 29.5 30.0 35.7

4: 37.1 44.2 34.1 30.3 31.8 33.1 34.1 32.9 36.3 25.8

Carry out an analysis of variance F test at significance level 0.01. State the appropriate hypotheses.

H0: μ1 = μ2 = μ3 = μ4 Ha: at least two μi's are unequal

Summarize the results in an ANOVA table. (Round your answers two decimal places.) Source df Sum of Squares Mean Squares f Treatments Error Total Give the test statistic. (Round your answer to two decimal places.)

ANOVA table

Source

SS

   df

MS

F

   p-value

Treatment

518.34

3

172.78

11.03

0.0000

Error

563.91

36

15.66

Total

1,082.26

39

f = 11.03

What can be said about the P-value for the test?

P-value < 0.001

State the conclusion in the problem context.

Reject H0. There is sufficient evidence to conclude that the total Fe differs for at least two of the four formations.

Excel Addon Megastat used.

One factor ANOVA

Mean

n

Std. Dev

26.16

10

3.450

Type1

24.71

10

4.420

Type2

30.00

10

2.872

Type3

33.97

10

4.793

Type4

28.71

40

5.268

Total

ANOVA table

Source

SS

   df

MS

F

   p-value

Treatment

518.342

3

172.7807

11.03

0.0000

Error

563.914

36

15.6643

Total

1,082.256

39


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