ISP have been allocated the address block 200.23.16.0/20 ISP, wants to divide its address block into...

ISP have been allocated the address block 200.23.16.0/20 ISP, wants to divide its address block into four equal sized address blocks and give one to each of four organizations. Write the address range and also subnet mask for each organization

Expert Solution

200.23.16.0
Let's convert all octets to binary separately
Converting 200 to binary
Divide 200 successively by 2 until the quotient is 0
   > 200/2 = 100, remainder is 0
   > 100/2 = 50, remainder is 0
   > 50/2 = 25, remainder is 0
   > 25/2 = 12, remainder is 1
   > 12/2 = 6, remainder is 0
   > 6/2 = 3, remainder is 0
   > 3/2 = 1, remainder is 1
   > 1/2 = 0, remainder is 1
Read remainders from the bottom to top as 11001000
So, 200 of decimal is 11001000 in binary
200 in binary is 11001000

Converting 23 to binary
Divide 23 successively by 2 until the quotient is 0
   > 23/2 = 11, remainder is 1
   > 11/2 = 5, remainder is 1
   > 5/2 = 2, remainder is 1
   > 2/2 = 1, remainder is 0
   > 1/2 = 0, remainder is 1
Read remainders from the bottom to top as 10111
So, 23 of decimal is 10111 in binary
23 in binary is 00010111

Converting 16 to binary
Divide 16 successively by 2 until the quotient is 0
   > 16/2 = 8, remainder is 0
   > 8/2 = 4, remainder is 0
   > 4/2 = 2, remainder is 0
   > 2/2 = 1, remainder is 0
   > 1/2 = 0, remainder is 1
Read remainders from the bottom to top as 10000
So, 16 of decimal is 10000 in binary
16 in binary is 00010000

Converting 0 to binary
Divide 0 successively by 2 until the quotient is 0
Read remainders from the bottom to top as
So, 0 of decimal is  in binary
0 in binary is 00000000

==================================================================================
||    200.23.16.0 in binary notation is 11001000.00010111.00010000.00000000    ||
==================================================================================

Answer:
---------
address range for organization 1:
----------------------------------
11001000.00010111.00010000.00000000 - 11001000.00010111.00010011.11111111
in decimal it is 200.23.16.0 - 200.23.19.255

address range for organization 2:
----------------------------------
11001000.00010111.00010100.00000000 - 11001000.00010111.00010111.11111111
in decimal it is 200.23.20.0 - 200.23.23.255

address range for organization 3:
----------------------------------
11001000.00010111.00011000.00000000 - 11001000.00010111.00011011.11111111
in decimal it is 200.23.24.0 - 200.23.27.255

address range for organization 4:
----------------------------------
11001000.00010111.00011100.00000000 - 11001000.00010111.00011111.11111111
in decimal it is 200.23.28.0 - 200.23.31.255

subnet mask is /22
in dotted decimal notation it is 255.255.252.0

venereology answered 1 month ago

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