Question

In: Computer Science

An ISP is granted a block 10.48.0.0/16. The ISP wants to allocate addresses as follows: Group...

An ISP is granted a block 10.48.0.0/16. The ISP wants to allocate addresses as follows:

Group 1: 16 customers, each with 64 addresses

Group 2: 64customers, each with 16 addresses

Group 3: 16customers, each with 32 addresses.

a.Find the subnet mask, first and last addresses of 4th customer of each group.

b.Find the number of addresses available with the ISP for future customers

Expert Solution

a) Block = 10.48.0.0/16

Group 1 : Each customer needs 64 addresses which means bits = 6 bits are needed for each host, the prefix length is : 32-6 = 26 bits. The addresses are :

Customer	First Address	Last Address
1	10.48.0.0/26	10.48.0.63/26
2	10.48.0.64/26	10.48.0.127/26
3	10.48.0.128/26	10.48.0.191/26
4	10.48.0.192/26	10.48.0.255/26
16	10.48.3.192/26	10.48.3.255/26

So 4th customer of 1st group: Subnet mask : 255.255.255.192, First Address: 10.48.0.192/26, Last Address: 10.48.0.255/26

Group 2: Each customer needs 16 addresses which means = 4 bits are needed for each host, the prefix length is: 32-4 = 28 bits. The addresses are:

Customer	First Address	Last Address
1	10.48.4.0/28	10.48.4.15/28
2	10.48.4.16/28	10.48.4.31/28
3	10.48.4.32/28	10.48.4.47/28
4	10.48.4.48/28	10.48.4.63/28
16	10.48.4.240/28	10.48.4.255/28
64	10.48.7.240/28	10.48.7.255/28

So 4th customer of 2nd group: Subnet mask : 255.255.255.240, First Address: 10.48.4.48/28, Last Address: 10.48.4.63/28

Group 3: Each customer needs 32 addresses which means = 5 bits are needed for each host, the prefix length is: 32-5 = 27 bits. The addresses are:

Customer	First Address	Last Address
1	10.48.8.0/27	10.48.8.31/27
2	10.48.8.32/27	10.48.8.63/27
3	10.48.8.64/27	10.48.8.95/27
4	10.48.8.96/27	10.48.8.127/27
16	10.48.9.240/27	10.48.9.255/27

So 4th customer of 3rd group: Subnet mask : 255.255.255.224, First Address: 10.48.8.96/27, Last Address: 10.48.8.127/27

b) Number of granted addresses to the ISP: 2^16 = 65536 as the block address is 10.48.0.0/16

Number of addresses used by group 1 users: 16*64 = 1024 addresses

Number of addresses used by group 2 users: 64*16 = 1024 addresses

Number of addresses used by group 3 users: 16*32 = 512 addresses

Total number of addresses used = 1024+1024+512 = 2560 addresses

Number of available addresses = 65536 - 2560 = 62976 addresses

venereology answered 2 years ago

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