In: Chemistry
Hi, To obtain the resolution of this exercise we must consider the law of Charles, it is a law that describes gases and relates the volume and temperature of a certain amount of ideal gas, maintained at a constant pressure, through a constant of direct proportionality. Expressing as follows: Where V1 is the initial volume, T1 is the initial temperature (absolute, it is kelvin), V2 is the final volume and T2 is the final temperature (absolute) We know V1, T1 and T2. V2 is our incognita but first the temperatures must be transformed to absolute. To do this, they are in degrees Celsius that by adding 273.15 we can obtain them at all, Kelvin: Next, we substitute and clear the incognita: CLEARANCE SUBSTITUTION V1= 148L T1= 358.15K T2= 288.15K V2=? Therefore, for a temperature of 288.15 K the container will have a volume of 119L. If you liked the resolution, a thumbs up would help me a lot. Thank you very much and greetings. Successes