Question

In: Physics

a bottle of alluminium (1L ) at 20 C is filled to the top with mercury....

a bottle of alluminium (1L ) at 20 C is filled to the top with mercury. The bottle is then heated to 110 C.

How much mercury will spill?  

Expert Solution

Important constants needed for the calculation :

Coefficient of linear expansion of aluminium

Coefficient of volume expansion of aluminium bottle,

Coefficient of volume expansion of Mercury,

Given that :

Volume of the aluminium bottle (V) = 1 L

Initial temperature (Ti) = 20°C

Final temperature (Tf) = 110°C

Temperature difference, = 110 - 20 = 90°C

Solution :

Increase in volume of Mercury =

= 0.0162 L

Increase in the volume of Al bottle =

= 0.00621 L

Amount of Mercury spilled out is the difference between volume increased in Mercury and volume increased in bottle

ie, Volume of Mercury spilled = 0.0162 - 0.00621

= 0.00999 L Hg

By converting into mL,

Volume of Mercury spilled out = 9.99 mL

Some extra notes :

genius_generous answered 2 years ago

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