Question

In: Statistics and Probability

Let W be a random variable that takes values 1 to 6 with equal probability. a)...

Let W be a random variable that takes values 1 to 6 with equal probability.

a) Write the PMF. 


b) Calculate the mean and variance of W and z=10 W.

Solutions

Expert Solution

W be a random variable that takes values 1 to 6 with equal probability

so, each will have probability of 1/6 = 0.1667

a)

so, PMF will be

W P(W)
1 0.1667
2 0.1667
3 0.1667
4 0.1667
5 0.1667
6 0.1667

b)

W P(W) W*P(W) W² * P(W)
1 0.1667 0.167 0.167
2 0.1667 0.333 0.667
3 0.1667 0.500 1.500
4 0.1667 0.667 2.667
5 0.1667 0.833 4.167
6 0.1667 1.000 6.000
P(W) W*P(W) W² * P(W)
total sum = 1 3.5 15.16667

mean = E[W] = ΣW*P(W) =            3.5
          
E [ W² ] = ΣW² * P(W) =            15.1667
          
variance = E[ W² ] - (E[ W ])² =            2.91667

-----------------------------------------

Z=10W

Z P(Z) Z*P(Z) Z² * P(Z)
10 0.1667 1.667 16.667
20 0.1667 3.333 66.667
30 0.1667 5.000 150.000
40 0.1667 6.667 266.667
50 0.1667 8.333 416.667
60 0.1667 10.000 600.000
P(Z) Z*P(Z) Z² * P(Z)
total sum = 1 35 1516.667

mean = E[Z] = ΣZ*P(Z) =            35
          
E [ Z² ] = ΣZ² * P(Z) =            1516.666667
          
variance = E[ Z² ] - (E[ Z ])² =            291.6666667


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