Question
In: Statistics and Probability
1. Let z be a random variable with a standard normal distribution. Find the indicated probability....
1. Let z be a random variable with a standard normal distribution. Find the indicated probability. (Round your answer to four decimal places.)
P(−2.13 ≤ z ≤ −0.35) =
2. Assume that x has a normal distribution with the specified mean and standard deviation. Find the indicated probability. (Round your answer to four decimal places.)
μ = 14.6; σ = 3.9
P(10 ≤ x ≤ 26) =
3. A person's blood glucose level and diabetes are closely related. Let x be a random variable measured in milligrams of glucose per deciliter (1/10 of a liter) of blood. Suppose that after a 12-hour fast, the random variable x will have a distribution that is approximately normal with mean μ = 82 and standard deviation σ = 30. Note: After 50 years of age, both the mean and standard deviation tend to increase. For an adult (under 50) after a 12-hour fast, find the following probabilities. (Round your answers to four decimal places.)
(a) x is more than 60
(b) x is less than 110
(c) x is between 60 and 110
(d) x is greater than 125 (borderline diabetes starts at
125)
Solutions
orchestra answered 1 year agoRelated Solutions
a) Let z be a random variable with a standard normal distribution. Find the indicated probability....
a) Let z be a random variable with a standard normal
distribution. Find the indicated probability. (Round your answer to
four decimal places.)
P(−2.02 ≤ z ≤ −0.31) =
Shade the corresponding area under the standard normal
curve.
b) Assume that x has a normal distribution with the
specified mean and standard deviation. Find the indicated
probability. (Round your answer to four decimal places.)
μ = 50; σ = 15
P(40 ≤ x ≤ 47) =
c) Find z such...
A: Let z be a random variable with a standard normal distribution. Find the indicated probability....
A: Let z be a random variable with a standard normal
distribution. Find the indicated probability. (Round your answer to
four decimal places.)
P(z ≤ 1.23) =
B: Let z be a random variable with a standard normal
distribution. Find the indicated probability. (Round your answer to
four decimal places.)
P(z ≥ −1.13) =
C: Let z be a random variable with a standard normal
distribution. Find the indicated probability. (Round your answer to
four decimal places.)
P(−1.87 ≤ z...
Let z be a random variable with a standard normal distribution. Find the indicated probability. (Round...
Let z be a random variable with a standard normal distribution.
Find the indicated probability. (Round your answer to four decimal
places.) P(−0.84 ≤ z ≤ 0) =
Shade the corresponding area under the standard normal
curve.
Let z be a random variable with a standard normal distribution. Find the indicated probability. (Round...
Let z be a random variable with a standard normal
distribution. Find the indicated probability. (Round your answer to
four decimal places.)
P(z ≥ −1.12) =
Shade the corresponding area under the standard normal curve.
1. a.) Let z be a random variable with a standard normal distribution. Find the indicated...
1.
a.) Let z be a random variable with a standard normal
distribution. Find the indicated probability. (Enter your answer to
four decimal places.) P(−2.20 ≤ z ≤ 1.01) =
b.) Let z be a random variable with a standard normal
distribution. Find the indicated probability. (Round your answer to
four decimal places.) P(−1.76 ≤ z ≤ −1.17) =
c.) Assume that x has a normal distribution with the
specified mean and standard deviation. Find the indicated
probability. (Round your answer to...
Let z be a random variable with a standard normal distribution. Find “a” such that P(|Z|...
Let z be a random variable with a standard normal
distribution.
Find “a” such that P(|Z| <A)= 0.95
This is what I have:
P(-A<Z<A) = 0.95
-A = -1.96
How do I use the symmetric property of normal distribution to make
A = 1.96?
My answer at the moment is P(|z|< (-1.96) = 0.95
Let z be a random variable with a standard normal distribution. Find P(0 ≤ z ≤...
Let z be a random variable with a standard normal distribution.
Find P(0 ≤ z ≤ 0.46), and shade the corresponding area under the
standard normal curve. (Use 4 decimal places.)
Question 3 options: | | Let Z denote a standard normal random variable. Find the probability...
Question 3 options:
|
|
Let Z denote a standard normal random variable. Find the
probability P(Z < 0.81)? The area to the LEFT of 0.81?
----------------------------------------
Enter in format X.XX rounding UP so one-half
(1/2) is 0.50 and two-thirds (2/3) is 0.67 with rounding. Enter
-1.376 as -1.38 with rounding. NOTE: DO NOT ENTER
A PERCENTAGE (%).
|
|
Let Z denote a standard normal random variable. Find the
probability P(Z > -1.29)? The area to the RIGHT of...
Find the indicated probability using the standard normal distribution. P(z < -0.39)
Find the indicated probability using the standard normal
distribution. P(z < -0.39)
For a random variable Z, that follows a standard normal distribution, find the values of z...
For a random variable Z, that follows a standard normal
distribution, find the values of z required for these probability
values:
P(Z<z)=.5 =
P(Z<z)=.1587 =
P(Z<z)=.8413 =
Please show how to solve without using excel.
Please show all steps.
Thank you!
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