Question

In: Finance

Consider the following two cash flow series of payments: Series A is a geometric series increasing...

Consider the following two cash flow series of payments: Series A is a geometric series increasing at a rate of 4% per year. The initial cash payment at the end of year 1 is $1,000. The payments occur annually for 5 years. Series B is a uniform series with payments of value X occurring annually at the end of years 1 through 5. You must make the payments in either Series A or Series B. Click here to access the TVM Factor Table Calculator Your answer is incorrect. Try again. Determine the value of X for which these two series are equivalent if your TVOM is i = 6%. $ Carry all interim calculations to 5 decimal places and then round your final answer to the nearest dollar. The tolerance is ±5. Your answer is incorrect. Try again. If your TVOM is 8%, would you be indifferent between these two series of payments? Enter the PW for each series to support this choice. PW, Series A: $ PW, Series B: $ Carry all interim calculations to 5 decimal places and then round your final answer to the nearest dollar. The tolerance is ±5%. Your answer is incorrect. Try again. If your TVOM is 5%, would you be indifferent between these two series of payments? Enter the PW for each series to support this choice. PW, Series A: $ PW, Series B: $ Carry all interim calculations to 5 decimal places and then round your final answer to the nearest dollar. The tolerance is ±5.

Solutions

Expert Solution

Series A
Year Geometric Series TVOM F at 6% TVOM at 6%
C/f (n+1)=C/f( n)*1.04
1 2 3 4 5 6=3*5
1 1000 1000 1/1.06^1= 0.94340 943.39623
2 1000*1.04= 1040 1/1.06^2= 0.89000 925.59630
3 1040*1.04= 1081.60000 1/1.06^3= 0.83962 908.13222
4 1081.6*1.04= 1124.86400 1/1.06^4= 0.79209 890.99765
5.00000 1124.864*1.04= 1169.85856 1/1.06^5= 0.74726 874.18637
Total PW of the series 4.21236 4542.30876
PW of Series B should be EQUAL to PW of the payments under geometric Series A
Using P/A,i= 6%,n=5, 4.21236
4.21236*X=4542.30876
So, X=4542.30876/4.21236=
1078.3287
So,
the value of X for which these two series are equivalent if the TVOM is i = 6%=
1078
2… Series A
Year Geometric Series TVOM F at 8% TVOM at 8%
C/f (n+1)=C/f( n)*1.04
1 2 3 4 5 6=3*5
1 1000 1000 1/1.08^1= 0.92593 925.92593
2 1000*1.04= 1040 1/1.08^2= 0.85734 891.63237
3 1040*1.04= 1081.60000 1/1.08^3= 0.79383 858.60895
4 1081.6*1.04= 1124.86400 1/1.08^4= 0.73503 826.80862
5 1124.864*1.04= 1169.85856 1/1.08^5= 0.68058 796.18608
Total PW of the series 3.99271 4299.16195
PW of Series A 4299
PW of Series B 4304
(1078*3.99271)=
4304.14138
YES--given the tolerance is ±5%
3.. Series A
Year Geometric Series TVOM F at 5% TVOM at 5%
C/f (n+1)=C/f( n)*1.04
1 2 3 4 5 6=3*5
1 1000 1000 1/1.05^1= 0.95238 952.38095
2 1000*1.04= 1040 1/1.05^2= 0.90703 943.31066
3 1040*1.04= 1081.60000 1/1.05^3= 0.86384 934.32675
4 1081.6*1.04= 1124.86400 1/1.05^4= 0.82270 925.42840
5 1124.864*1.04= 1169.85856 1/1.05^5= 0.78353 916.61479
Total PW of the series 4.32948 4672.06155
PW of Series A 4672
PW of Series B 4667
(1078*4.32948)=
4667.17944
YES--given the tolerance is ±5

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