Question

Define a function named sumsinconv that accepts double precision variable theta, double precision variable alpha, and unsigned integer n, and returns the solution of expression

sin ⁡ ( ( n + 1 ) α 2 ) sin ⁡ ( θ + n α 2 ) sin ⁡ ( α 2 )

in C

Only show the function definition. Do not write an entire program with a main function. Just write the definition for function sumsinconv.

Answer 1

C CODE( function sumsinconv)

float sumsinconv(double teta, double alpha,unsigned int n)
{
  
double sol=sin((n+1)*alpha*alpha)*(sin(teta+n*alpha*alpha))*sin(alpha*alpha);
// expression for sin ⁡ ( ( n + 1 ) α 2 ) sin ⁡ ( θ + n α 2 ) sin ⁡ ( α 2 )
return sol;
}

FULL CODE

#include<stdio.h>
#include <math.h>
float sumsinconv(double teta, double alpha,unsigned int n);
void main()
{
double teta;
double alpha;
unsigned int n;

printf("\nEnter the value of teta:"); //input the values
scanf("%lf",&teta);
printf("\nEnter the value of alpha:");
scanf("%lf",&alpha);
printf("\nEnter the value of n :");
scanf("%d",&n);
double r=sumsinconv(teta,alpha,n); //function call
printf("\n solution for expression :%lf",r); //display output
}

float sumsinconv(double teta, double alpha,unsigned int n)
{
  
double sol=sin((n+1)*alpha*alpha)*(sin(teta+n*alpha*alpha))*sin(alpha*alpha);
// expression for sin ⁡ ( ( n + 1 ) α 2 ) sin ⁡ ( θ + n α 2 ) sin ⁡ ( α 2 )
return sol;
}

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