In: Chemistry
Is the ground state of cyclobutadiene a singlet or triplet?
Cyclobutadiene has singlet ground state with
D2h symmetry. This can be explained on the basis of
john-teller distortion. According to that principle, the non linear
molecule having degenerate ground state can undergo a distortion by
reducing its symmetry. In case of cyclobutadiene the expected
symmetry is D4h but due
to john teller distortion it behaves as a rectangular instead of
perfectly square planar and hence the symmetry is D2h.
As the distortion makes the structure change from square planar to
rectangular shape, there is the conformation of two single bond is
longer than two double bond which is also experimentally proved. So
that when it undergoes from square planar to rectangular shape, the
degenerate orbital in square planar state also became
non-degenerate in rectangular shape. out of the two degenerate
orbital one go higher energy and other goes lower energy to balance
overall energy and hence the all electrons in the ground state of
rectangular D2h become paired and hence it behaves as
ground state triplet. this can be better explained by following
image.