In: Math
A political pollster is conducting an analysis of sample results in order to make predictions on election night. Assuming a two-candidate election, if a specific candidate receives at least 55% of the vote in the sample, that candidate will be forecast as the winner of the election. You select a random sample of 100 voters. Complete parts (a) through (c) below.
a. What is the probability that a candidate will be forecast as the winner when the population percentage of her vote is 50.1%? The probability is nothing that a candidate will be forecast as the winner when the population percentage of her vote is 50.1%. (Round to four decimal places as needed.)
b.
What is the probability that a candidate will be forecast as
the winner when the population percentage of her vote is
55%? |
c.
What is the probability that a candidate will be forecast as
the winner when the population percentage of her vote is
49% (and she will actually lose the election)? |
d.
Suppose that the sample size was increased to
400. Repeat process (a) through (c), using this new sample size. Comment on the difference. |
(a)
Here we have
n=100 ,p = 0.501
The sampling distribution of sample proportion will be approximately normal with mean
and standard deviation
The z-score for is
Using z table, the probability that a candidate will be forecast as the winner is
(b)
Here we have
n=100 ,p = 0.55
The sampling distribution of sample proportion will be approximately normal with mean
and standard deviation
The z-score for is
Using z table, the probability that a candidate will be forecast as the winner is
(c)
Here we have
n=100 ,p = 0.49
The sampling distribution of sample proportion will be approximately normal with mean
and standard deviation
The z-score for is
Using z table, the probability that a candidate will be forecast as the winner is
(d)
Here we have
n=400 ,p = 0.501
The sampling distribution of sample proportion will be approximately normal with mean
and standard deviation
The z-score for is
So the probability that a candidate will be forecast as the winner is
------------------------------------
Here we have
n=400 ,p = 0.55
The sampling distribution of sample proportion will be approximately normal with mean
and standard deviation
The z-score for is
So the probability that a candidate will be forecast as the winner is
-----------------------------------
Here we have
n=400 ,p = 0.49
The sampling distribution of sample proportion will be approximately normal with mean
and standard deviation
The z-score for is
So the probability that a candidate will be forecast as the winner is